The velocity of a particle moving along a line is given by e(t) = 4t - 15, where v(t) is in ft/s and 0S55 What is the object's total displacement on the interval [0, 5]? %3D -5 feet 10 feet 5 feet -25 feet None of the listed answers.
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![The velocity of a particle moving along a line is given by e(t) = 4t - 15, where v(t) is in ft/s and
0S55 What is the object's total displacement on the interval [0, 5]?
%3D
-5 feet
10 feet
5 feet
-25 feet
None of the listed answers.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4f496499-3588-4e79-98dd-6c561ba3f10b%2F8e23289e-e102-46e5-abad-f205e91529cd%2F8r0piuj.jpeg&w=3840&q=75)
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- Figure OQ1.13 shows two vectors D1 and D2. Which of the possibilities (a) through (d) is the vector D22D1, or (e) is it none of them? Figure OQ1.13The velocity of an object is given by, = u + at V ds dt. where, u is the initial velocity, a is the acceleration, and ₺ is the time in seconds. Solve the differential equation to obtain the displacement, s, given that at t = 0, s = 7 (metres) : 1 if u = 3 ms ¹, a = 2.4 ms 2, calculate the displacements at t = 4.9 seconds. Give your answer to 2 decimal places.The displacement of a particle is given by s = 3t3 - 42t2 + 109t - 39 where s is in feet and t is in seconds. Plot the displacement, velocity, and acceleration as functions of time for the first 11 seconds of motion. After you have made the plots, answer the questions. Questions: Att = 2.4 ft. v= ft/sec. a = ft/sec? sec, Att= 5.4 i ft, v= i ft/sec, a = i ft/sec? S= sec, Att = 8.5 ft. v= i ft/sec, a = i ft/sec? sec, The velocity is zero when t = i sec and when t = i sec
- A particle’s velocity along the x-axis is described by v(x) = A x + B x2, where x is in meters, v is in meters per second, A = 3.56, and B = -1.5 what is the acceleration, in meters per second squared, of the particle position at x = 2.31m?The displacement of a particle is given by s = 3t3 - 53t2 + 115t - 62 where s is in feet and t is in seconds. Plot the displacement, velocity, and acceleration as functions of time for the first 14 seconds of motion. After you have made the plots, answer the questions.Questions: At t = 3 sec, s = ft, v = ft/sec, a = ft/sec2 At t = 7.7 sec, s = ft, v = ft/sec, a = ft/sec2 At t = 11.5 sec, s = ft, v = ft/sec, a = ft/sec2 The velocity is zero when t = sec and when t = secThe displacement of a particle is given by s= 5t³ - 59t² + 87t-68 where s is in feet and t is in seconds. Plot the displacement, velocity, and acceleration as functions of time for the first 9 seconds of motion. After you have made the plots, answer the questions. Questions: Att = 0.9 S= i ft, v = ft/sec, a = ft/sec² sec, Att = 5 sec, S= ft, v= ft/sec² ft/sec, a = Att = 6.6 sec, i S= ft, v = ft/sec, a = ft/sec² The velocity is zero when t = i Mi i sec and when t = i i sec
- The displacement of a particle is given by s = 4t3 - 60t² + 100t - 58 where s is in feet and t is in seconds. Plot the displacement, velocity, and acceleration as functions of time for the first 13 seconds of motion. After you have made the plots, answer the questions. Questions: At t = 1.8 S= i 49.072 ft,v= -77.12 ft/sec, a = -76.8 ft/sec sec, At t = 6.6 S= i 19263.104 ft,v= -169.28 ft/sec, a = 38.4 ft/sec sec, Att = 9.8 S = -1075.632 V = ft/sec,a 115.2 ft/sec sec, The velocity is zero when t = i 217.9795 ft, Mi 10218.304 sec and when t = i 22.0205 secI took 2.28km and converted it to 2280 meters then divided by 3200 and ended up with .71m/s but it keeps saying that its incorrect. Im not sure where I keep messing up. John walks 1.80 kmkm north, then turns right and walks 1.40 kmkm east. His speed is 1.60 m/sm/sduring the entire stroll. What is the magnitude of his displacement, from beginning to end? (2.28) If Jane starts at the same time and place as John, but walks in a straight line to the endpoint of John's stroll, at what speed should she walk if she wants to arrive at the endpoint just when John does?The displacement of a particle is given by s = 2t3 - 41t2 + 90t - 39 where s is in feet and t is in seconds. Plot the displacement, velocity, and acceleration as functions of time for the first 16 seconds of motion. After you have made the plots, answer the questions. Questions: Att = 2.6 sec, S = ft,v = ft/sec,a = i ft/sec Att = 7.5 sec, S = ft,v = ft/sec,a = i ft/sec Att = 13.5 S = i ft,v = i ft/sec,a = i ft/sec sec, The velocity is zero when t = i sec and whent= i sec
- in the Cartesian coordinate system, a particles in x-position is defined by x = 8t ft, where the time t is in seconds. if the equation for the path is it? y = x2/10, calculate the magnitude of the acceleration at t = 2 sec in ft/sec². X5 240042003 2100/2009 Sr0 I bro, do steny pd bedrivesh 21 plod prillot sont s to addons/esse ont geelm mit el v stories, fogalm [ ^v. + or -1] · 18.5 = 0. ci uhod sat di Inocentes e ashoshib sviting ont ban a stobiolos, skulitis doin o to the mont 1920 191 wobod alumnet ant prize 1921m ni 298 2 = & morto pindler 2+/X+0/01 SA car takes 5.0 s to go from v=0 m/s to v=24 m/s at constant acceleration. If you wish to find the disance traveled using the equation d=1/2at squared, what value should you use for a? Express your answer to two significant figures and includ the appropraite units.The displacement of a particle is given by s = 2t3 - 32t2 + 89t - 32 where s is in feet and tis in seconds. Plot the displacement, velocity, and acceleration as functions of time for the first 13 seconds of motion. After you have made the plots, answer the questions. Questions: Att= 2.9 sec, ft, v= i ft/sec, a = i ft/sec2 At t = 6.3 sec, i ft. v= ft/sec, a = i ft/sec? At t = 11.6 i ft. v= ft/sec, a = i ft/sec2 sec, The velocity is zero when t = i sec and whent= i sec
