The transmission loss function of a power network consisting of 2 generators at different buses can be expressed as follows: Ploss = 0.002P₁² +0.001P₂², where P₁, and P₂ are the generators' power outputs. If P₁ = 150 MW, P₂ = 100 MW, the penalty factor of bus 1 and 2 are respectively equal to: Select one: O a. PF1=2, PF2=1 O b. PF1=1.5, PF2=1.2 O c. None of these Od. PF1-2.5, PF2=1.25

The transmission loss function of a power network consisting of 2 generators at different buses can be expressed as follows: Ploss = 0.002P₁² +0.001P₂², where P₁, and P₂ are the generators' power outputs. If P₁ = 150 MW, P₂ = 100 MW, the penalty factor of bus 1 and 2 are respectively equal to: Select one: O a. PF1=2, PF2=1 O b. PF1=1.5, PF2=1.2 O c. None of these Od. PF1-2.5, PF2=1.25

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter12: Power System Controls

Section: Chapter Questions

Problem 12.13P

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