The symmetry factor β was determined to be 0.4 for an activation controlled Ag deposition process. At overpotential η = -0.400 V the current density was found to be j = -5.125 A/dm2. What is the value of the exchange current density j0, and what will be the current density j [A/dm2 ] at overpotential of -0.003 V?.

The symmetry factor β was determined to be 0.4 for an activation controlled Ag deposition process. At overpotential η = -0.400 V the current density was found to be j = -5.125 A/dm2. What is the value of the exchange current density j0, and what will be the current density j [A/dm2 ] at overpotential of -0.003 V?.

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter17: Applications Of Infrared Spectrometry

Section: Chapter Questions

Problem 17.11QAP

See similar textbooks

Similar questions

For n = 10 mV, i = 0.62 mA through 2 cm² Pt electrode in H*/H2. What %3D will be i for (a) n = 100 mV (b) ŋ = -100 mV. Assume the symmetry factor (a) as 0.5, H*+e → ½ H2. (Hint: Use Butler-Volmer Equation)
How long will it take to dissolve 2 mg of metal A (atomic weight 100) in a solution containing A2+ from a metal electrode with area of 1.5 cm2 at an overpotential of = 0.2 V? The exchange current density (j0) for A is 3x10-3 A/cm2, the temperature T=298 K and the symmetry factor =0.4.
The transfer coefficient of a certain electrode in contact with M2+ and M3+ in aqueous solution at 25 °C is 0.42. The current density is found to be 17.0 mA cm2 when the overpotential is 105 mV. What is the overpotential required for a current density of 72 mA cm−2? Hint: See hint to Exercise E19D.1(a).
Calculate the absorbance at 280 nm that is expected for a 17 microM solution of peptide GRAYISH, if a 10-cm cuvette is used. For the extinction coefficient, take into account that e280(Trp) = 5690 M-1 cm-1 and e280(Tyr) = 1280 M-1 cm-1.
An atomic beam is designed to function with (a) cadmium, (b) mercury. The source is an oven maintained at 380K with a small slit of dimensions 1.0cm x 1.0 x 10-3cm. The vapor pressure of cadmium is 0.13 Pa nd that of mercury is 12 Pa at this temperature. What is the atomic current (the number of atoms per second) in the beams?
A Dubosq colorimeter consists of a cell of fixed path length and a cell of variable path length. By adjusting the length of the latter until the transmission through the two cells is the same. the concentration of the second solution can be inferred from that of the former. Suppose that a plantdye of concentration 25 μg dm-3 is added to the fixed cell. the length of which is 1.55 em. Then a solution of the same dye. but of unknown concentration. is added to the second cel l. It is found that the same t ransmittance is obtained when the length of the second cel l is adjusted to 1.18 em. What is the concentration of the second solution?
write a summary of each of the techniques for measuring vacancyconcentrations, noted therein. (1) Measurements of the quenched-in residual electricalresistivity of aluminium rapidly cooled from temperatures be-low about 800 K with initial quenching rates of 2 × 106 K s−1give the enthalpy of formation of monovacancies H F1V =(0.65 ± 0.01) eV.(2) Comparison of the quenching data with high-temperature differential-dilatometry data gives the monova-cancy formation entropy SF1V = (0.76 ± 0.4)kB (kB =Boltzmann’s constant) and the low-temperature resistivity perunit concentration of vacancies ρ1V = (1.9 ± 0.1) μm.(3) The binding enthalpy of divacancies in Al is H B2V =(0.17 5 ± 0.02 5) eV. This is in agreement with earlier ex-perimental determinations by Doyama and Koehler 48) and byLevy et al. 49, 50) but in marked contrast to the claim of Carlinget al., 23) based on computations with the generalized gradi-ent approximation, that in Al H B2V is zero or even negativeand therefore the…
At 520 nm with a 1.00 cm cell a 8.24 ppm solution of KMnO4 has a transmittance of 0.126. What is the molar absorptivity of KMnO4 at 520 nm?
What are transference numbers and how are they related to ionic mobilities?
For a tungsten carbene (catalyst) binding to THF (ligand) at 25 oC in per-deuterotoluene solvent, the chemical shift of the unbound catalyst alpha hydrogen was determined to be 794.6 Hz and the peak for the fully bound catalyst alpha hydrogen was observed at 842.4 Hz. Furthermore, the binding constant (or formation constant) Kf was found to be 15.40 M-1. Given the following initial concentrations of catalyst and ligand, calculate the percent THF bound you would expect to see at 25 oC. Record your answer to the nearest tenths of a percent, as a number with no units (Ex. 3.4% ----> enter "3.4") Co = 1.000 M Lo = 0.1000 M
The resolution product of Ag2S03 is 1.5 x 10-14. Ag2SO3 (k) + 2e + 2 Ag (k) + SO32- Calculate EO for Ag* + e + Ag E° = + 0,799 V |
The resolution product of Ag2SO3 is 1.5 x 10-14. Calculate E0 for Ag2SO3 (k) + 2e- ↔ 2 Ag (k) + SO32-. Ag + + e- ↔ Ag E0 = + 0.799 V A. + 0.799 VB. + 0.803 VC. + 0.020 VD. + 0.390 V