The shaft of a motor has a length of 15 times its diameter and has a maximum twist of 1.5 degrees when twisted at 2.5 KN-m torque. If the modulus of rigidity of the shaft is 83 Gpa, find the shaft diameter in m
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Q: Calculate the shaft diameter on rigidity basis if torsional moment is 195000 N-mm, length of shaft…
A: Write down the given values along with suitable variables. ϴ = 0.6° G = 79300 N/ mm2 T = 195000 N-mm…
Q: In a shaft of 5 m length a stress of 75 MPa was developed. Find the diameter of the shaft if the…
A: Given data: τ=75 MPaL=5 mθ=3°G=83 GPa Need to determine the diameter of the shaft.
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Q: 5. The shaft of a motor has a length of 15 times its diameter and has a maximum twist of 1.5 degrees…
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Q: 40 Steel d = 30 mm A G= 83 GPa 1.2 m
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Q: Problem 1
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The shaft of a motor has a length of 15 times its diameter and has a maximum twist of 1.5
degrees when twisted at 2.5 KN-m torque. If the modulus of rigidity of the shaft is 83 Gpa,
find the shaft diameter in m
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- A hollow steel shaft is stressed to 55 MPa by a torque of 100,000 ft-lb. If the inside diameter is 2/3 of the outside diameter and if G = 83 GPa, find the angle of twist in degrees if the shaft is 5 meters long.The axis ABCD receives a torque of 500Nm from the motor and transmits movement to other devices, by means of belts and pulleys connected at B and C. If it is known that the torques exerted on pulleys B and C are as shown In the figure, determine the minimum radius the shaft must have. You should consider that at point D of the motor there is a bearing that acts as a support for the shaft as at point A. The material of the shaft and its allowable shear stress are indicated in the drawing.Determine:to. Free-Body diagram.b. Shear force diagrams.c. Bending moment diagrams.d. Identification of the critical point of the axis.e. Calculation of the axis radius. tperm=80MPaA solid shaft of diameter 10 mm is subjected to a torque of 15 N/m. considering modulus of rigidity of the material as 0.8 X 10^5 N/mm². Find the angle of twist (in degree) over length of 250 mm? O 3.12 degree O 4.08 degree O 1.32 degree O 2.74 degree
- The hollow rod shown below is 2.99 meters long and is subjected to a torque of 988 Nm at end B. The diameter of the rod is 30 mm and has a wall thickness of 5 mm. The shear modulus of the material is 80 GPa, calculate the angle of twist in radians at B. TNm B metersA hollow steel shaft is stressed to 35 MPa by a torque of 200000Nm. Determine the outside diameter in mm if the inside diameter is 2/3 of the outside diameter both in mm.The outer diameter of the shaft is 175 mm and the diameter ratio is 1.25. Find the polar modulus of the shaft is mm3. The polar modulus of shaft (in mm³)
- A shaft required to transmit 50kW of power will be running at 100rev/min. The maximum twist in 3m length of the shaft is limited to 1.5 degree. If the maximum torque is 30 percent more than mean or average torque. Assume entirely elastic action and take modulus of rigidity for the shaft material G = 135 GN/?2. Determine the following:a. Diameter of the shaft.b. Maximum shear stress developed in the shaft. I need answer ASAP. Thank you!A torsional bar is subjected to two external torques (10Nm and 5Nm) and a distributed torque(15Nm/m) at the locations indicated in the picture. The angle of twist at A (z = 0) is 0. Theshear modulus is 2GPa., if the bar has both A and C fixed (i.e., the torque applied at C is replaced by a fixed support), find the angle of twist at B.3. The two identical shafts, 1 and 2, are built into supports at their left ends. Gears mounted on their right ends engage a third gear that is attached to shaft 3. Determine the torques in shafts 1 and 2 when the 500N -m torque is applied to shaft 3. 40 500 Nm 80 Dimensions in mm 4. A 4-ft-long tube with the cross section shown in the figure is made of aluminum. Find the torque that will cause a maximum shear stress of 10 000 psi. Use G = 4 x 106 psi for aluminum. +4 in. → 0.04 in. 0.08 in.´ 5. Two steel springs are arranged in series as shown. The upper spring has 36 turns of 100-mm- diameter wire on a mean radius of 350 mm. The lower spring consists of 24 turns of 75-mm diameter wire on a mean radius of 245 mm. If the ultimate shearing stress in either spring must not exceed 692 MPa, (a) compute the maximum value of P and total elongation using factor of safety equal to 1.5. (b) What is the equivalent spring constant? Use G = 83 GPa. 2 of 2 4 in. wwwww.-
- A shaft ABCD is fixed at end D and has torques acting at points A, B, and C as shown below. The bearing support between A and B allows free rotation. If we know that A = −0.382 rad, A/B = 0.358 rad, and B/C = −0.233 rad, calculate the absolute twist of the shaft at point C(oc) and enter it in rad (radians) correct to 3 significant digits below. Make sure to include the sign if it is negative noting that CCW rotations are positive and CW rotations are negative. 150 N.m 280 N.m B 40 N-m DA shaft made from acrylic is subjected to the three torques indicated below. The acrylic has a shear modulus of 1.7 GPa. Determine: a. The twist at the end D if the diameter if the shaft is 100 mm. b. The minimum shaft diameter if Tallow = 10 MPa 200 N•m A 800 N•m 300 mm B 400 N•m 600 mm C 600 mmCalculate the shaft diameter on rigidity basis if torsional moment is 195000 N-mm, length of shaft is 1000 mm. Permissible angle of twist per meter is 0.6° and take G = 79300 N/mm² O 108.21 mm O 39.33 mm O 6.99 mm O 48.93 mm