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- Which of the following DO NOT match? O Plastic Moment --- FyZ O Long Column -- Fcr = 0.658^(Fy/Fe)[Fy] O Beam Strength --- OMn O Allowable Load --- Rn/22-A teel ptd is streteky between fwo rigid walls ard carries a tensile load f GO0ON at c f the alowate Stress is not to exceed 130 MPa at -4C, what is the minimum diameter f as ard E= J00 GPa. the nod? Figuro: ST LQ1 Delermine the design (ultimate) bending mement for the beam sections showen belowi- 300 mm AG0 mn 330 530 4 bars A es 70 (a) fy s20 Mla - 34 Mla SI0 mm fe'= 28 MAA An 820 mn Ans: prh= 448ma) (Ans: Sectien has2- A 2m COPPER BAR SUBJECTEO TO A TENSILE IS SUSPENDED FROM A LOAD IBO KN SUPPORTED BY TWO IDENTICAL PIN THAT S pOSIS AS SHON OF THE LOWER AFPLIED TENSILE POSTS SUPPORT THE STEEL DETERMINE THE TOTAL DEFORMATION END OF THE LOAD HINT: NOTE THAT THE STEEL PIN WHERE THE COFPER BAR IS ATTACHED. COPPER BAR DUE TO STEEL POST L=0.5m A= 4500mm E- 200GPA COPFER BAR L- am A= 4800 Mn E- l20 GPa 180KN10/10 find the tensile stress in upper plate in section 3-3 80 kN 80 kN 8-bolt DIA. 10 MM 80 kN 80 kN 8-bolt DIA. 10 MM 10 MPа О 12.5 MPa 15 MPa 8.5 MPa O no one O ---.. O- O O 300mm 8 mm1.8-4 Lateral bracing for an elevated pedestrian walkway is shown in the figure part (a). The thickness of the clevis plate 1. = 16 mm and the thickness of the gusset plate t = 20 mm [see figure part (b)]. The maximum force in the diagonal bracing is expected to be F = 190 kN. If the allowable shear stress in the pin is 90 MPa and the allowable bearing stress between the pin and both the clevis and gusset plates is 150 MPa, what is the minimum required diameter dmin of the pin? Pin Diagonal brace (a) (© Barry Goodno)rectanqular seetion with width bz250 and depth h= 500mm is to carcry a A m %3D design bending moment M= 260KN•M, The conerete is of greade e30 and the tensile steel is of HRB400. The tension reinforzce. ment A, is requined.Q.2. The rigid bar AB, atrached to two verti cal rods as shown in Fig (e), is horizontal before the lead p is applied. If the load pe so kN, ditermine its Vertical mmovement. Aluminum Steel A300 mm 200 G A500 mm R-70 GN -3m- Fig (2)Qそ- d Iム the force in member (B) (B G-) Max foves that can tん Then Compute Moving Lead in both dink be de ve loped (GH) alony the bottom cord? 140 h 35 w H.4 A flanged bolt coupling has ten 12-mm di ameter steel bolts on 500 mm diameter b olt circle and six 16 mm diameter aluminu m bolts on 300 mm diameter bolt circle. T he maximum shear stresses of the materi als are 60 MPa in steel and 40 MPa in al uminum. Use G = 80 GPa for steel and 3 0 GPa for aluminum. What is the maximu m required shear strength of each alumin um bolt to determine the maximum torqu e that can be applied to the system? Dra wing not included in this problem.7 Enercise:- 30 long with is subjected to a Assuming deformation is entirely elastic and manimum allowable elongation tensile 30000y that the is 0.3 mm while manimum. allowable reduction in, digmeter is 0.015mm. choose amory below only. candidate meeting requirent E (GPa) A cylindrical rod 100 mm diameter of 12 mm load of 30000 N. Aluminium alloy Bronze Titanium allow 70 100 110 U(Poiss ons vahi) 0.33 0.34 0.3DO NO OWAVE www.oukpak.com F06 unic 30KN 150 KN 20KN 3m =30" SOLVE FOR ACL SUPPORT 2m HINGE REACTIONS LN DICATE THE DIRECTICNS e UNITC 20 A B imSEE MORE QUESTIONS