the reaction 3 H2(g) + N2 (g)  *double arrow here* 2 NH3(g) at 472 ℃, equilibrium is established when [H2] = 0.0200 M, [N2] = 0.0100 M and [NH3] = 5.37 x 10-8 M. a) Write the equilibrium constant expression for this reaction. (Use ^ for exponents) b) Calculate the equilibrium constant for this reaction.

World of Chemistry, 3rd edition
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Chapter17: Equilibrium
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Problem 17A
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For the reaction 3 H2(g) + N2 (g)  *double arrow here* 2 NH3(g) at 472 ℃, equilibrium is established when [H2] = 0.0200 M, [N2] = 0.0100 M and [NH3] = 5.37 x 10-8 M.

a) Write the equilibrium constant expression for this reaction. (Use ^ for exponents)

b) Calculate the equilibrium constant for this reaction. 

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