The period of a torsion pendulum, for small angular displacements, is given by: T=2π√1/K where I is the body's moment of inertia and K is the pendulum's torsion constant. For k= (4.86x10^4 +0.02x10^4) dyn/cm and T = (5.106±0.001) s, measured experimentally, determine the moment of inertia of the torsion pendulum.

University Physics Volume 1
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ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
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Chapter1: Units And Measurement
Section: Chapter Questions
Problem 81AP: Consider the equation s=s0+v0t+a0t2/2+j0t3/6+s0t4/24+ct5/120 , were s is a length and t is a time....
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The period of a torsion pendulum, for small angular displacements, is given
by: T=2πνί/κ
where I is the body's moment of inertia andk is the pendulum's torsion
constant.
For k= (4.86x10^4 + 0.02x10^4) dyn/cm and T= (5.106 + 0.001) s, measured
experimentally, determine the moment of inertia of the torsion pendulum.
Transcribed Image Text:The period of a torsion pendulum, for small angular displacements, is given by: T=2πνί/κ where I is the body's moment of inertia andk is the pendulum's torsion constant. For k= (4.86x10^4 + 0.02x10^4) dyn/cm and T= (5.106 + 0.001) s, measured experimentally, determine the moment of inertia of the torsion pendulum.
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