The oxalate ion, C2O42-, acts as a ligand to form complex ions with the Mn2+ ion. Mn2+ + C2O42- ⇄ MnC2O4 K1 = 7.9×103 [Mn(C2O4)2]2- ⇄ MnC2O4 + C2O42- K2 = 1.26×10-2 What is the equilibrium constant for the reaction below? Mn2+ + 2C2O42- ⇄ [Mn(C2O4)2]2-
The oxalate ion, C2O42-, acts as a ligand to form complex ions with the Mn2+ ion. Mn2+ + C2O42- ⇄ MnC2O4 K1 = 7.9×103 [Mn(C2O4)2]2- ⇄ MnC2O4 + C2O42- K2 = 1.26×10-2 What is the equilibrium constant for the reaction below? Mn2+ + 2C2O42- ⇄ [Mn(C2O4)2]2-
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter19: Complex Ions
Section: Chapter Questions
Problem 26QAP
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Question
250.0 mL of 0.010 M Mn(NO3)2 are mixed with 1.0 L of 1.0 M Na2C2O4. The oxalate ion, C2O42-, acts as a ligand to form complex ions with the Mn2+ ion.
Mn2+ + C2O42- ⇄ MnC2O4 K1 = 7.9×103
[Mn(C2O4)2]2- ⇄ MnC2O4 + C2O42- K2 = 1.26×10-2
What is the equilibrium constant for the reaction below?
Mn2+ + 2C2O42- ⇄ [Mn(C2O4)2]2-
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