The Otto engine intakes 0.4 kg of air at 100 kPa and 300 K. The air is compressed compression ratio of 12. Combustion adds 600 kJ/kg of heat. Pi T. Use air data at the assumed average temperature of 800 K. 300-80s oireuns =0. 800 a) Fill out the tables below State 1 State 2 State 3 State 4 100 kPa 100K Pressure 30ok 0-86 Temperature 300 K Specific Volume 0.86 0.08 0.08 Process 1→2 Process 2-3 Process 3-4 Process 4 1 Net 50 Au Lkg. Q Q [kJ 443 m lkg. W [kJ m b) What is the net work from one cycle of the engine (in kJ)? c) What is the efficiency of the engine? h

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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The Otto engine intakes 0.4 kg of air at 100 kPa and 300 K. The air is compressed at a
compression ratio of 12. Combustion adds 600 kJ/kg of heat.
Pi
Use air data at the assumed average temperature of 800 K.
300-80s
nolteups
=0.375
800
enstali
a) Fill out the tables below
State 1
State 2
State 3
State 4
100 WPa
300k
0.86
Pressure
100 kPa
Tетрerature
300 K
0.86
0.08
0.08
Specific Volume
Process 1→2
Process 2→3
Process 3→4
Process 4→1
Net
Au
[kgl
Q [kJ
m Lkg.
W [kJ
m [kg.
L27
77
b) What is the net work from one cycle of the engine (in kJ)?
c) What is the efficiency of the engine? h
Qin
d) For Process 1->2, calculate Au using the specific heat and calculate work using the
appropriate work equation. How much difference is there between the two
approaches?
Constant
Volume
Transcribed Image Text:The Otto engine intakes 0.4 kg of air at 100 kPa and 300 K. The air is compressed at a compression ratio of 12. Combustion adds 600 kJ/kg of heat. Pi Use air data at the assumed average temperature of 800 K. 300-80s nolteups =0.375 800 enstali a) Fill out the tables below State 1 State 2 State 3 State 4 100 WPa 300k 0.86 Pressure 100 kPa Tетрerature 300 K 0.86 0.08 0.08 Specific Volume Process 1→2 Process 2→3 Process 3→4 Process 4→1 Net Au [kgl Q [kJ m Lkg. W [kJ m [kg. L27 77 b) What is the net work from one cycle of the engine (in kJ)? c) What is the efficiency of the engine? h Qin d) For Process 1->2, calculate Au using the specific heat and calculate work using the appropriate work equation. How much difference is there between the two approaches? Constant Volume
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