You are in an elevator that is initially at rest. At t=0, it heads downward and speeds up as afunction of time. It experiences a velocity given by v(t) = (−2.00t²ĵ)²mSa) What is the normal force that you experience at t=1.20 s? Assume you have a mass of70.0 kg.b) How far did the elevator drop in 1.20 s?

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Description: You are in an elevator that is initially at rest. At t=0, it heads downward and speeds up as afunction of time. It experiences a velocity given by v(t) = (−2.00t²ĵ)²mSa) What is the normal force that you experience at t=1.20 s? Assume you have a mas

Answered: the normal force that you experience

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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You are in an elevator that is initially at rest. At t=0, it heads downward and speeds up as a
function of time. It experiences a velocity given by v(t) = (−2.00t²ĵ)²
m
S
a) What is the normal force that you experience at t=1.20 s? Assume you have a mass of
70.0 kg.
b) How far did the elevator drop in 1.20 s?

Expert Solution

Step 1

Given:

Initially elevator is at rest.

Velocity of elevator in downward direction is $v (t) = (- 2 t^{2} \hat{j}) m / s$

Mass of the person is $m = 70 kg$

Note:

$1 N = 1 kg \cdot m / s^{2}$

Find:

(a) Normal force experienced by person at time $t = 1.20 s$

(b) Distance traveled by elevator in time $t = 1.20 s$

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