The 'H NMR spectrum of chloroethane (CH3CH,CI) recorded on a 500 MHz NMR spectrometer consists of signals at chemical shifts of 1.48 ppm and 3.57 ppm. Calculate the frequency, downfield from TMS, of each absorption. Be sure to answer all parts. frequency of 1.48 ppm signal = Hz frequency of 3.57 ppm signal = Hz

Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
ChapterL3: Carbon (13c) Nmr Spectroscopy
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Problem 9E
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The 'H NMR spectrum of chloroethane (CH3CH2CI) recorded on a 500 MHz NMR spectrometer
consists of signals at chemical shifts of 1.48 ppm and 3.57 ppm. Calculate the frequency, downfield
from TMS, of each absorption. Be sure to answer all parts.
nts
frequency of 1.48 ppm signal =
Hz
еВook
frequency of 3.57 ppm signal
Hz
Drint
Transcribed Image Text:2 3 attempts left Check my work The 'H NMR spectrum of chloroethane (CH3CH2CI) recorded on a 500 MHz NMR spectrometer consists of signals at chemical shifts of 1.48 ppm and 3.57 ppm. Calculate the frequency, downfield from TMS, of each absorption. Be sure to answer all parts. nts frequency of 1.48 ppm signal = Hz еВook frequency of 3.57 ppm signal Hz Drint
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