The following program simulates a vending machine panel. The program gets an integer that represents the user's selected item, and then outputs a dispensing message. Only 8 items are for purchase. Ex: The input 2 results in the message "Dispensing item 2". Arrange the following lines to handle two exceptions. If the user enters an item number that is not for purchase, the program throws an Exception with the message "Try again", outputs the exception message, and then tries again. If the user enters a non- integer input, the program throws an Input MismatchException, outputs "Fatal error", and then exits. Not all lines are used in the solution. How to use this tool Unused System.out.println("Fatal error"); System.out.println(excpt); askForInput = false; askFor Input = true; } catch (Exception excpt) { catch (InputMismatch Exception excpt) { } System.out.println(excpt.toString()); System.out.println (excpt.getMessage()); Vending Machine.java import java.util.Scanner; import java.util. InputMismatchException; Load default template... public class Vending Machine { public static void main (String [] args) { Scanner scnr = new Scanner(System.in); int itemNumber = 0; boolean askForInput = true; while (askFor Input) { try { itemNumber scnr. nextInt(); if ((itemNumber <= 0) || (itemNumber > 8)) { throw new Exception ("Try again"); } System.out.println("Dispensing item " + itemNumbe askForInput= false;
The following program simulates a vending machine panel. The program gets an integer that represents the user's selected item, and then outputs a dispensing message. Only 8 items are for purchase. Ex: The input 2 results in the message "Dispensing item 2". Arrange the following lines to handle two exceptions. If the user enters an item number that is not for purchase, the program throws an Exception with the message "Try again", outputs the exception message, and then tries again. If the user enters a non- integer input, the program throws an Input MismatchException, outputs "Fatal error", and then exits. Not all lines are used in the solution. How to use this tool Unused System.out.println("Fatal error"); System.out.println(excpt); askForInput = false; askFor Input = true; } catch (Exception excpt) { catch (InputMismatch Exception excpt) { } System.out.println(excpt.toString()); System.out.println (excpt.getMessage()); Vending Machine.java import java.util.Scanner; import java.util. InputMismatchException; Load default template... public class Vending Machine { public static void main (String [] args) { Scanner scnr = new Scanner(System.in); int itemNumber = 0; boolean askForInput = true; while (askFor Input) { try { itemNumber scnr. nextInt(); if ((itemNumber <= 0) || (itemNumber > 8)) { throw new Exception ("Try again"); } System.out.println("Dispensing item " + itemNumbe askForInput= false;
Chapter11: Exception Handling
Section: Chapter Questions
Problem 1CP
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I need help with fixing this java
![The following program simulates a vending machine panel. The program gets an integer that represents the user's selected item,
and then outputs a dispensing message. Only 8 items are for purchase. Ex: The input 2 results in the message "Dispensing item
2".
Arrange the following lines to handle two exceptions. If the user enters an item number that is not for purchase, the program
throws an Exception with the message "Try again", outputs the exception message, and then tries again. If the user enters a non-
integer input, the program throws an InputMismatchException, outputs "Fatal error", and then exits.
Not all lines are used in the solution.
How to use this tool
Unused
System.out.println("Fatal error");
System.out.println(excpt);
askFor Input = false;
askForInput = true;
}
catch (Exception excpt) {
catch (InputMismatchException excpt) {
}
System.out.println(excpt.toString());
System.out.println(excpt.getMessage());
Vending Machine.java
import java.util.Scanner;
import java.util. InputMismatchException;
Load default template...
public class Vending Machine {
public static void main (String [] args) {
Scanner scnr = new Scanner(System.in);
int itemNumber = 0;
boolean askForInput = true;
while (askFor Input) {
try {
itemNumber = scnr.nextInt ();
if ((itemNumber <= 0) || (itemNumber > 8)) {
throw new Exception ("Try again");
}
System.out.println("Dispensing item " + itemNumbe
askFor Input = false;](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4e135d5c-f867-4afd-9f0d-b505f4f19664%2Ff1331c56-d694-4ee6-8c8d-5ecd876c39c4%2F8or9738_processed.png&w=3840&q=75)
Transcribed Image Text:The following program simulates a vending machine panel. The program gets an integer that represents the user's selected item,
and then outputs a dispensing message. Only 8 items are for purchase. Ex: The input 2 results in the message "Dispensing item
2".
Arrange the following lines to handle two exceptions. If the user enters an item number that is not for purchase, the program
throws an Exception with the message "Try again", outputs the exception message, and then tries again. If the user enters a non-
integer input, the program throws an InputMismatchException, outputs "Fatal error", and then exits.
Not all lines are used in the solution.
How to use this tool
Unused
System.out.println("Fatal error");
System.out.println(excpt);
askFor Input = false;
askForInput = true;
}
catch (Exception excpt) {
catch (InputMismatchException excpt) {
}
System.out.println(excpt.toString());
System.out.println(excpt.getMessage());
Vending Machine.java
import java.util.Scanner;
import java.util. InputMismatchException;
Load default template...
public class Vending Machine {
public static void main (String [] args) {
Scanner scnr = new Scanner(System.in);
int itemNumber = 0;
boolean askForInput = true;
while (askFor Input) {
try {
itemNumber = scnr.nextInt ();
if ((itemNumber <= 0) || (itemNumber > 8)) {
throw new Exception ("Try again");
}
System.out.println("Dispensing item " + itemNumbe
askFor Input = false;
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