The following experimental data was collected by a student: 0.0020 M Fe(NO3)3 mL Trial 1 2 3 4 Blank 5.00 5.00 5.00 5.00 5.00 0.0020 KSCNmL 2.00 3.00 4.00 5.00 0.00 Water mL 3.00 2.00 1.00 0.00 5.00 5. STANDARD (18.00 mL 0.200 M Fe(NO3)3 mL +2.00 mL 0.0020 KSCN mL) Use the data given above to calculate K. for trial#1. (SHOW ALL STEPS!) ABS 0.251 0.344 0.428 0.559 0.000 ABS = 0.979
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- 351145 TECHNO Define fundamental unit with an example. Why is the unit of force called a derived unit? ic a derived unit? Give its two examples. measurement Dats : D Graphite and iodine a y shine. Explain it with suitable yeasons. Graphite and are non-metals but the iodine are non- metals but REDMI NOTE 10 PRO KBYLWHARNA THAPA A chemical propertie39/99/2021 17:361. In your pharmacy you have a balance with a sensitive requirement of 7mg; 10,25,50 and 100ml graduated cylinder; and 1 oz apothecary and 4-ounce apothecary conical cylinder. What is the minimum measurable volume in ml using the graduated cylinder?a. 5b. 20c. 1d. 257.9 mL of 0.161 M Fe(NO3)3 and 24.7 mL of 0.557 M Ca(NO3)2 a) [ Fe3+ ] = 9.32 M; [ NO3- ] = 55.5 M; [ Ca2+ ] = 13.8 Mb) [ Fe3+ ] = 0.00932 M; [ NO3- ] = 0.0555 M; [ Ca2+ ] = 0.0138 Mc) [ Fe3+ ] = 0.161 M; [ NO3- ] = 3.59 M; [ Ca2+ ] = 0.557 Md) [ Fe3+ ] = 0.113 M; [ NO3- ] = 0.672 M; [ Ca2+ ] = 0.167 Me) [ Fe3+ ] = 0.0133 M; [ NO3- ] = 0.144 M; [ Ca2+ ] = 0.0460 M
- 1.5 x 103 uL ------> mLA student dissolves a Jefferson nickel to make 100.00 mL of solution in a volumetric flask. The student takes a 5.00 mL5.00 mL aliquot of the first solution and dilutes it to make 100.00 mL100.00 mL of a second solution. The student places a sample of the second solution in a cuvette for analysis using spectrophotometry. The molarity of the copper solution in the cuvette was determined by spectrophotometric analysis to be 2.90×10−2 M Cu.2.90×10−2 M Cu. Calculate the mass of copper in the Jefferson nickel used to make the first solution.CH₂-COOH Citric acid has the formula HO-C-COOH I CH₂-COOH CH2–CDD - Na* + HD-C-CDD- Na CH₂-COO- COO-Na A 25.0 mL sample of a concentrated citrus fruit cordial component (e.g. for lime juice), used in the food & drinks industry, was diluted to 250 mL in a graduated volumetric flask. A 25.0 mL sample of this diluted solution, required, on average, 22.5 mL of a standard 0.100 molar sodium hydroxide solution using phenolphthalein indicator for the titration end-point. A) 0.0075 Assuming all the acid in the cordial was citric acid, calculate the concentration of the acid in g/mL in the original solution. B) 0.576 D and is tribasic acid, forming the tri-sodium salt on complete neutralisation with sodium hydroxide. 1.44 0.00225
- You have been provided with data of 2 groundwater samples. The following are the major constituents (in mg/l): Parameter Sample 1 Sample 2 Са 35 27 Mg 33 5.75 Na 28 16 K 1.3 0.7 НСОЗ 177 327 SO4 15 22 Cl 6.9 4.4 Boron 4.0 1.0 EC (dS/m) 0.511 0.237 TDS (mg/l) ? Tasks: 1. Check for Ionic balance. 2. Estimate TDS in mg/L 3. Show data in a. Vertical bar graph b. Vector diagram c. Pattern diagram d. Circular diagram e. Trilinear diagram f. Schoeller semilogarithmic diagram 4. Calculate %Na, SAR, Hardness 5. Discuss suitability of these waters for agricultural use. 6. Is this water suitable for drinking? What treatments will be needed to make it drinkable? 7. Is there any seawater intrusion in these aquifers? Expalin. 8. Make any other relevant commentsAn analysis of 0.7 kg dry soil sample (having a volume of 500 mL) showsthat sample contains 35 mg naphthalene (C10H8). Based on the results of this analysis.a) What is the density of the soil in g/cm3?b) What is the concentration of naphthalene in this sample in terms of mass percentage (%m/m) and ppmm?LU eFu X NCH X E NCH X Ь Му х LU Oef X U Oef X U Oef x LU Oef x LU Oef x LU Oef x n 202 x n Oef x Mic x A docs.google.com/forms/d/e/1FAlpQLSfSGcE8gf218c6JoHMWME1A8Nydf8M4g1yG93D-2LPpoMj_g/formResponse Question 1: The compound in Figure 1 can be obtained from the oyster mushroom. It is used to slow the production of cholesterol in the body. Which of the following functional groups are not present in this compound? * O Alcohol O Ether Ester Alkene O Carboxylic acid Figure 1 HO Lavostatin 08:56 P Type here to search 25°C Sunny 2021/11/19
- 37. A student recorded the following data for the alcohol content of a blood sample: % C.H5OH: 0.084, 0.068, and 0.079. Calculate the 95% confidence limit for the average of this data.U eFu X NCH X NCH X ь Му х LU Oef x n Oef x U Oef x O Oef x LU Oef x U Oef x U 202 x n Oef x h Mic x A docs.google.com/forms/d/e/1FAlpQLSFSGcE8gf218c6JoHMWME1A8Nydf8M4g1yG93D-2LPpoMij_g/formResponse Question 37: Give the preferred IUPAC name of the product of the reaction in Figure 37. [Use lowercase letters. Do not use spaces except where required in the official name.] * Jou antwoord Figure 37 CH3 1 LIAIH4 CH3-CH2-C-c=N 2 H* CH3 09:15 P Type here to search 25°C Sunny 2021/11/19Dr. Caras was characterizing a cytochrome (an iron containing protein) from a new strain of bacteria. He obtained eight measurements of the percent iron in the protein: 0.2409%, 0.2404%, 0.2394%, 0.2399%, 0.2515%, 0.2393%, 0.2409%, and 0.2392%. Calculate the mean (x) and standard deviation (s) for these results. % S = Use the Grubbs test to determine if one of these values is an outlier. What is the value of Galculated? Gcalculated = Should this potential outlier be rejected with 95% confidence? Critical values of G can be found in this table. The potential outlier should be rejected. The potential outlier should be kept.