The following data were obtained in E106: Mass of aluminum calorimeter = 46.4 g Mass of calorimeter with water = 185.7 g Mass of metal specimen = 32.9 g !! Initial temperature of water = 27.5°C Initial temperature of metal specimen 100°C Specific heat of aluminum = 0.2174 cal/g Co Final temperature of the system = 30.5°C %3! Specific heat of water = 1.00 cal/g Co How much heat is lost by the metal specimen? O - 30.26 cal O- 471.9 cal O- 448.16 cal O- 139.2 cal

University Physics Volume 2
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Chapter2: The Kinetic Theory Of Gases
Section: Chapter Questions
Problem 60P: A sample of neon gas (Ne, molar mass M=20.2 g/mol) at a temperature of 13.0 is put into a steel...
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Question 20
The following data were obtained in E106:
Mass of aluminum calorimeter = 46.4 g
Mass of calorimeter with water = 185.7 g
Mass of metal specimen =
32.9 g
Initial temperature of water = 27.5°C
Initial temperature of metal specimen = 100°C
Final temperature of the system = 30.5°C
Specific heat of aluminum = 0.2174 cal/g Co
Specific heat of water = 1.00 cal/g co
!!
How much heat is lost by the metal specimen?
O- 30.26 cal
O- 471.9 cal
O- 448.16 cal
O- 139.2 cal
Transcribed Image Text:Question 20 The following data were obtained in E106: Mass of aluminum calorimeter = 46.4 g Mass of calorimeter with water = 185.7 g Mass of metal specimen = 32.9 g Initial temperature of water = 27.5°C Initial temperature of metal specimen = 100°C Final temperature of the system = 30.5°C Specific heat of aluminum = 0.2174 cal/g Co Specific heat of water = 1.00 cal/g co !! How much heat is lost by the metal specimen? O- 30.26 cal O- 471.9 cal O- 448.16 cal O- 139.2 cal
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