The electric potential in a particular area varies with position as V(x) = ax2 - bx + c, where a = 2.9 V/m2, b = 13 V/m, and c = 11 V. Find the electric field vector E in this area in terms of the given variables. Be sure to include a unit vector for direction. What is the magnitude of the electric field, in volts per meter, at x = 1.0 m? What is the direction of the electric field at x = 1.0 m? What is the magnitude of the electric field, in volts per meter, at x = 5.0 m? What is the direction of the electric field at x = 5.0 m?
The electric potential in a particular area varies with position as V(x) = ax2 - bx + c, where a = 2.9 V/m2, b = 13 V/m, and c = 11 V. Find the electric field vector E in this area in terms of the given variables. Be sure to include a unit vector for direction. What is the magnitude of the electric field, in volts per meter, at x = 1.0 m? What is the direction of the electric field at x = 1.0 m? What is the magnitude of the electric field, in volts per meter, at x = 5.0 m? What is the direction of the electric field at x = 5.0 m?
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter20: Electric Potential And Capacitance
Section: Chapter Questions
Problem 20P: At a certain distance from a charged particle, the magnitude of the electric field is 500 V/m and...
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The electric potential in a particular area varies with position as V(x) = ax2 - bx + c, where a = 2.9 V/m2, b = 13 V/m, and c = 11 V.
Find the electric field vector E in this area in terms of the given variables. Be sure to include a unit vector for direction.
What is the magnitude of the electric field, in volts per meter, at x = 1.0 m?
What is the direction of the electric field at x = 1.0 m?
What is the magnitude of the electric field, in volts per meter, at x = 5.0 m?
What is the direction of the electric field at x = 5.0 m?
Expert Solution
Step 1
The electric field strength is the negative of the potential gradient.
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