The dipole moment of the water molecule (H,O) is6.17 x 10-30 C.m. Consider a water molecule located at theorigin whose dipole moment p points in the positive x direction. Achlorine ion (CIx = 3.00 x 10-9 meters. Assume that this x value is muchlarger than the separation d between the charges in the dipole,so that the approximate expression for the electric field along thedipole axis can be used.Part Aof charge -1.60 x 10-19 C, is located atFind the magnitude of the electric force, ignoring the sign, that the water molecule exerts on the chlorine ion.• View Available Hint(s)6.57 • 1012N

Dipole moment of Water, pw = 6.17×10-30 C.mCharge on Chlorine ion, qCl = -1.6×10-19 CDistance, x =…

Answered: The dipole moment of the water molecule…

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter5: Electric Charges And Fields

Section: Chapter Questions

Problem 107P: A water molecule consists of two hydrogen atoms bonded with one oxygen atom. The bond angle between...

See similar textbooks

Related questions

Concept explainers

Question

The dipole moment of the water molecule (H,O) is
6.17 x 10-30 C.m. Consider a water molecule located at the
origin whose dipole moment p points in the positive x direction. A
chlorine ion (CI
x = 3.00 x 10-9 meters. Assume that this x value is much
larger than the separation d between the charges in the dipole,
so that the approximate expression for the electric field along the
dipole axis can be used.
Part A
of charge -1.60 x 10-19 C, is located at
Find the magnitude of the electric force, ignoring the sign, that the water molecule exerts on the chlorine ion.
• View Available Hint(s)
6.57 • 1012
N

Expert Solution

Step 1

$D i p o l e m o m e n t o f W a t e r, p_{w} = 6.17 \times 10^{- 30} C . m C h a r g e o n C h l o r i n e i o n, q_{C l} = - 1.6 \times 10^{- 19} C D i s \tan c e, x = 3 \times 10^{- 9} m C o u l o m b' s c o n s \tan t, k = 8.99 \times 10^{9} N m^{2} / C^{2}$

We assume that x is much larger than the distance d between the charges in dipole.

So, for electric field we have,

$E = \frac{2 k p}{x^{3}}$

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions