The content of a file containing UTF-8 Unicode encoded text is given by the following sequence of bytes in hexadecimal notation: f0 9f 94 a8 20 e2 88 a7 20 f0 9f 8e 93 Oa c) Which line end convention is used? What are other popular line end conventions?
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- What bit string is stored in memory for the following 8 character string when using ASCII representation? (Use 8 bit cells): 822-7003TMin - 1 (write in decimal representation): -TMin: -TMax: TMAX> AQuestion 11 Not yet answered P Flag question A computer system uses 8 bits to represent floating-point values. The 8 bits are organised as follows: The first bit is a sign bit (0 for positive, 1 for negative). The middle 3 bits are the exponent, which uses bias of 3. The last 4 bits are the significand, which is normalised in the same way as the significand is normalised in IEEE-754 formats. The format does not reserve any special values. The following arithmetic operation is performed on this system: 00011000 x 11000110 The result is then stored in the same 8-bit floating-point format. What is the relative error of the stored result comapred to the value of the result of the arithmetic operation? Answer s are rounded to 5 decimal places. O a. None of the other answers. O b. 0.03030% O c. 0.03125% O d. 0.97865% O e. 0%
- 10-1010 Express the following bit patterns in hexadecimal notation: Question 5 10100000101%3D 110001111011= 000010111110 001101010011 To submit your assignment: Please answer the question on the Lab Document and submit your file througWhat is the difference between absolute code and relocatable code?The following c# application builds a BitArray of five Byte values (1,2,3,4,5) and shows each byte in its correct binary form:
- Convert the following decimal number into it's IEEE 754 Floating Point representation. -23.5625 What is the following hexadecimal number in binary format? OxA47D What is the IEEE 754 floating point representation of the following number: 93.751165:0100 B84518 1165:0103 BB3478 1165:0106 01C3 1165:0108 48 1165:0109 4B 1165:010A 891E0001 1165:010E CD20 MOV MOV ADD AX, 1845 BX,7834 BX, AX DEC AX DEC MOV BX (0100], BX INT 20 You have used DEBUG to unassemble the above code. The entire program is bytes long. 8 16 64 010E 1165Q1: Normalize the following numbers (a) ABCDEFH (b) 1.0000000000001B (c) 10^4-10^3 Q2: Code 100001/17 as 4 bytes BFPN.