The combined correction due to curvature and refraction (in m) for a distance of 1 km on the surface of Earth is..
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- The combined correction due to curvature and refraction (in m) for a distance of 2 km is:Difference between Seiemic retledian and repraction:Based from the Figure, a vertical angle of +13°45’ is read to a target 1.23 m above point B. The measured inclined distance S is 823.29 m and the elevation of point A is 123.65 m above the datum. The height of the instrument at A is 1.35 m. Consider the effect of earth’s curvature and refraction. Determine the difference in elevation between A and B Determine the elevation of B
- In the Newton's Rings apparatus, the light of 615nm and convex-planar lens of radius of curvature 5.6cm are used. When a an unknown liquid is introduced into the air space between the lens and the plate, the diameter of the 13th dark ring is 0.560mm. Find the index of refraction of the liquid. State your answer to the nearest 0.0001.Refraction Rod r V. Level Line B. Z Earth Level Line GI Curvature Aelev Horizontal at C, C Level Line H hi A Figure 4.2 Trigonometric Leveling for Long LinesThe combined correction for curvature and refraction for a distance of 3400 m will be nearly 0.2 m 0.4 m 0.6 m 0.8 m
- For a distance of 2km on the curved earth surface, determine the equivalent correction of curvature and refraction for correct length measurement.Compute the refraction error for a distance 1824.1 m. Answer: Choose... +From an instrument set up an object was observed at a distance of 5.4 km away. Neglecting the effect of refraction, determine how much would the horizontal line depart from the level line due to earth's curvature. Select the correct response: 2.29m 1.91m 2.67m 1.85m 4
- A theodolite is set up at station A. The RL of instrument axis is 212,250 m. The angle of elevation to the top of a 4 m long staff, held vertical at station B, is 7°. The horizontal distance between stations A and B is 400 m. Neglecting the errors due to curvature of earth and refraction, the RL (in m (round off to three decimal places) of station B isCompute the error of curvature and refraction of a distance 1459.92 m Answer:A man standing on a beach can see the top of a lighthouse 25 km away. If the eye of the man is 1.5 m above sea level, then determine the height of the lighthouse above sea level considering earth’s curvature and refraction correction.