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The circuit in (Figure 1) is scaled so that the 4 k resistor is replaced by a 20 k resistor and the 5 nF capacitor is replaced by a 100 pF capacitor. Part A What is the scaled value of inductor? Figure 300u(t) V 1 of 1 ☐ ΜΑ Units L= Value Submit Request Answer Part B ? Choose the correct expression for v, in the scaled circuit? Vo= (256e-400000t vo (256e 400000 = Vo= (4e +4e-100000+)u(t) V -4e-100000+)u(t) V -400000t 256e-100000+)u(t) V Vo= (4e 400000+ +256e-100000+)u(t) V 4 ΚΩ 21 ΚΩ www + Submit Request Answer + Vo80 mH 5 nF i. Provide Feedback

The circuit in (Figure 1) is scaled so that the 4 k resistor is replaced by a 20 k resistor and the 5 nF capacitor is replaced by a 100 pF capacitor. Part A What is the scaled value of inductor? Figure 300u(t) V 1 of 1 ☐ ΜΑ Units L= Value Submit Request Answer Part B ? Choose the correct expression for v, in the scaled circuit? Vo= (256e-400000t vo (256e 400000 = Vo= (4e +4e-100000+)u(t) V -4e-100000+)u(t) V -400000t 256e-100000+)u(t) V Vo= (4e 400000+ +256e-100000+)u(t) V 4 ΚΩ 21 ΚΩ www + Submit Request Answer + Vo80 mH 5 nF i. Provide Feedback

Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter21: Resistive-capacitive Series Circuits
Section: Chapter Questions
Problem 6RQ: A 15-F AC capacitor is connected in series with a 50 resistor. The capacitor has a voltage rating...
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The circuit in (Figure 1) is scaled so that the 4 k resistor is replaced by a 20 k resistor and the 5 nF capacitor is replaced by a 100 pF capacitor. Part A What is the scaled value of inductor? Figure 300u(t) V 1 of 1 ☐ ΜΑ Units L= Value Submit Request Answer Part B ? Choose the correct expression for v, in the scaled circuit? Vo= (256e-400000t vo (256e 400000 = Vo= (4e +4e-100000+)u(t) V -4e-100000+)u(t) V -400000t 256e-100000+)u(t) V Vo= (4e 400000+ +256e-100000+)u(t) V 4 ΚΩ 21 ΚΩ www + Submit Request Answer + Vo80 mH 5 nF i. Provide Feedback
Transcribed Image Text:The circuit in (Figure 1) is scaled so that the 4 k resistor is replaced by a 20 k resistor and the 5 nF capacitor is replaced by a 100 pF capacitor. Part A What is the scaled value of inductor? Figure 300u(t) V 1 of 1 ☐ ΜΑ Units L= Value Submit Request Answer Part B ? Choose the correct expression for v, in the scaled circuit? Vo= (256e-400000t vo (256e 400000 = Vo= (4e +4e-100000+)u(t) V -4e-100000+)u(t) V -400000t 256e-100000+)u(t) V Vo= (4e 400000+ +256e-100000+)u(t) V 4 ΚΩ 21 ΚΩ www + Submit Request Answer + Vo80 mH 5 nF i. Provide Feedback
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