The arc length of a given function is determined by √1+f'(2) dz Find the length of f(x)= (2/3) (x-1)/² between x-9 and x-36. The working integral equation will be the f(x) is equal to The final answer is Choose.... Choose... Choose... ÷ : +

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- square root of (x-1)
- 126 units
- x-1
- integral of square root of (1+squareroot of (x-1)) dx with the limits from 9 to 36
- 189 units
- integral of square root of (1+squareroot of (x-1) squared) dx with the limits from 9 to 36

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The arc length of a given function is determined by f1 + f(zdz.
Find the length of f(x)= (2/3) (x-1)/2 between x-9 and x-36.
The working integral equation will be the Choose...
f(x) is equal to
The final answer is
Choose...
Choose...
+
0
●
Transcribed Image Text:The arc length of a given function is determined by f1 + f(zdz. Find the length of f(x)= (2/3) (x-1)/2 between x-9 and x-36. The working integral equation will be the Choose... f(x) is equal to The final answer is Choose... Choose... + 0 ●
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