The angle (with respect to the vertical) of a simple pendulum is given by 0= 0mcos[(5.88 rad/s)t + p]. If at t = 0, 0 = 0.0450 rad and d0/dt = -0.160 rad/s, what are (a) thephase constant p and (b) the maximum angle 0m? (Hint: Don't confuse the rate d0/dt at which 0changes with the w of the SHM.)PivotpointL.1e\LIs= LOF,coseFgsine(a)(b)

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The angle (with respect to the vertical) of a simple pendulum is given by e = Omcos[(5.88 rad/s)t + p]. If at t = 0, 0 = 0.0450 rad and de/dt = -0.160 rad/s, what are (a) the phase constant o and (b) the maximum angle Om? (Hint: Don't confuse the rate d0/dt at which 0 changes with the w of the SHM.)

The angle (with respect to the vertical) of a simple pendulum is given by e = Omcos[(5.88 rad/s)t + p]. If at t = 0, 0 = 0.0450 rad and de/dt = -0.160 rad/s, what are (a) the phase constant o and (b) the maximum angle Om? (Hint: Don't confuse the rate d0/dt at which 0 changes with the w of the SHM.)

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter12: Oscillatory Motion

Section: Chapter Questions

Problem 29P: The angular position of a pendulum is represented by the equation = 0.032 0 cos t, where is in...

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