The activation energy for a first order reaction is 100.6 kj/mole at 121°C. What is the rate constant at this temperature if the frequency factor is 1 x 10^12
The activation energy for a first order reaction is 100.6 kj/mole at 121°C. What is the rate constant at this temperature if the frequency factor is 1 x 10^12
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter11: Chemical Kinetics: Rates Of Reactions
Section: Chapter Questions
Problem 49QRT
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The activation energy for a first order reaction is 100.6 kj/mole at 121°C. What is the rate constant at this temperature if the frequency factor is 1 x 10^12
Expert Solution
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Step 1
Activation energy (Ea) = 100.6 KJ/mol ...Or
because 1 KJ = 1000 J so,
= 100.6 KJ/mol × (1000 J / 1 KJ)
= 100.6 × 1000 J/mol.
Temperature (T) = 121°C ....Or
because k = 0°C + 273 so, T becomes -
= 121°C + 273
= 394 k
Frequency factor (A) = 1 × 1012
Rate constant (K) = ?
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