The accompanying information is a set of coded experimental data on the compressive strength of a particular alloy at various values of the concentration of some additive. Complete parts (a) and (b) below. Click the icon to view the compressive strength data. (a) Estimate the quadratic regression equation µyx = ßo +ß₁×₁ +ß₂ײ. ŷ= 19.19 + ( 0.994) ×₁ + ( − 0.020 ) ׳₁ (Round the constant to two decimal places as needed. Round all other constants and coefficients to three decimal places as needed.) (b) Test for lack of fit of the model. State the null and alternative hypotheses. Ho H₁ An exponential model would fit the data better than a quadratic model. There is no lack of fit for the model. There is a lack of fit for the model. A linear model would fit the data better than a quadratic model. A cubic model would fit the data better than a quadratic model. Bearing Data Concentration, Compressive Strength, x 10.0 y 25.3 10.0 27.5 10.0 28.6 15.0 29.6 15.0 31.1 15.0 27.8 20.0 31.1 20.0 32.6 20.0 29.7 25.0 31.7 25.0 30.1 25.0 32.4 30.0 29.4 30.0 30.6 30.0 32.8

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 94E
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I need help with part b the null and alternative hypotheses for both H0 and H1 please

The accompanying information is a set of coded experimental data on the compressive strength of a particular alloy at various values of the concentration of some additive. Complete parts (a) and (b) below.
Click the icon to view the compressive strength data.
(a) Estimate the quadratic regression equation µyx = ßo +ß₁×₁ +ß₂ײ.
ŷ= 19.19 + ( 0.994) ×₁ + ( − 0.020 ) ׳₁
(Round the constant to two decimal places as needed. Round all other constants and coefficients to three decimal places as needed.)
(b) Test for lack of fit of the model.
State the null and alternative hypotheses.
Ho
H₁
An exponential model would fit the data better than a quadratic model.
There is no lack of fit for the model.
There is a lack of fit for the model.
A linear model would fit the data better than a quadratic model.
A cubic model would fit the data better than a quadratic model.
Transcribed Image Text:The accompanying information is a set of coded experimental data on the compressive strength of a particular alloy at various values of the concentration of some additive. Complete parts (a) and (b) below. Click the icon to view the compressive strength data. (a) Estimate the quadratic regression equation µyx = ßo +ß₁×₁ +ß₂ײ. ŷ= 19.19 + ( 0.994) ×₁ + ( − 0.020 ) ׳₁ (Round the constant to two decimal places as needed. Round all other constants and coefficients to three decimal places as needed.) (b) Test for lack of fit of the model. State the null and alternative hypotheses. Ho H₁ An exponential model would fit the data better than a quadratic model. There is no lack of fit for the model. There is a lack of fit for the model. A linear model would fit the data better than a quadratic model. A cubic model would fit the data better than a quadratic model.
Bearing Data
Concentration, Compressive Strength,
x
10.0
y
25.3
10.0
27.5
10.0
28.6
15.0
29.6
15.0
31.1
15.0
27.8
20.0
31.1
20.0
32.6
20.0
29.7
25.0
31.7
25.0
30.1
25.0
32.4
30.0
29.4
30.0
30.6
30.0
32.8
Transcribed Image Text:Bearing Data Concentration, Compressive Strength, x 10.0 y 25.3 10.0 27.5 10.0 28.6 15.0 29.6 15.0 31.1 15.0 27.8 20.0 31.1 20.0 32.6 20.0 29.7 25.0 31.7 25.0 30.1 25.0 32.4 30.0 29.4 30.0 30.6 30.0 32.8
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