The510-kg uniform beam is subjected to the three external loads shown. Compute the reactions at the support point O. The x-y planeis vertical. Positive values are to the right, up, and counterclockwise.1.0 m-Answers:MiAOx=Oy=Mo= i4.7 kN2.1 m38 kN-mBkNkN2.1 mkN.mC4.0 KNx The mass center G of the 1570-kg rear-engine car is located as shown in the figure. Determine the normal force under each tire whenthe car is in equilibrium. State any assumptions.Answers:GO-1276 mm-919 mm-Normal force under each of the front tires: Nf=Normal force under each of the rear tires: N₁ =iNN

Answered: Image /qna-images/answer/09aac3b6-5d91-4f97-a9ed-b45ca77e4352.jpg

The 510-kg uniform beam is subjected to the three external loads shown. Compute the reactions at the support point O. The x-y plane is vertical. Positive values are to the right, up, and counterclockwise. y

The 510-kg uniform beam is subjected to the three external loads shown. Compute the reactions at the support point O. The x-y plane is vertical. Positive values are to the right, up, and counterclockwise. y

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter5: Displacement And Force In Two Dimensions

Section: Chapter Questions

Problem 82A

See similar textbooks

Similar questions

The forearm shown below is positioned at an angle with respect to the upper arm , and a 5.0- kg mass is held in the hand. The total mass of the forearm and hand is 3.0 kg, and their center of mass is 15.0 cm from the elbow. (a) What is the magnitude of the force that the biceps muscle exerts on the forearm for =60 ? (b) What is the magnitude of the force on the elbow joint for the same angle? (c) How do these forces depend on the angle ?
(a) When opening a door, you push on it perpendicularly with a force of 55.0 N at a distance of 0.850m from the hinges. What torque are you exerting relative to the hinges? (b) Does it matter if you push at the same height as the hinges?
a) What is the mechanical advantage of a wheelbarrow, such as the one in Figure 9.24, if the center of gravity of the wheelbarrow and its load has a perpendicular lever arm of 5.50 cm, while the hands have a perpendicular lever arm of 1.02 m? (b) What upward force should you exert to support the wheelbarrow and its load if their combined mass is 55.0 kg? (c) What force does the wheel exert on the ground? Figure 9.24 (a) In the case of the wheelbarrow, the output force or load is between the pivot and the input force. The pivot IS the wheel's axle. Here, the output force is greater than the input force. Thus, a wheelbarrow enables you to lift much heavier loads than you could with your body alone. (b) In the case of the shovel, the input force is between the pivot and the load, but the input lever arm is shorter than the output lever arm. The pivot is at the handle held by the right hand. Here, the output force (supporting the shovel's load) is less than the input force (from the hand nearest the load), because the Input is exerted closer to the pivot than is the output
A painter of mass 87.8 kg is 1.45 m from the top of a 6.67-m ladder. The ladder rests against a wall. Friction between the ladder and the wall is negligible. The ladders mass is 5.50 kg. Assume the ladder is set up according to Occupational Safety and Health Administration standards so that it makes a 75.5 angle with the floor. a. What is the minimum coefficient of static friction required for the painters safety? b. Would rubber ladder tips on dry concrete be safe?
(i) If you are trying to loosen a stubborn screw from a piece of wood with a screwdriver and fail, should you find a screwdriver for which the handle is (a) longer or (b) fatter? (ii) If you are trying to loosen a stubborn bolt from a piece of metal with a wrench and fail, should you find a wrench for which the handle is (a) longer or (b) fatter?
The mass center G of the 1590-kg rear-engine car is located as shown in the figure. Determine the normal force under each tire when the car is in equilibrium. State any assumptions. Answers: -1251 mm-942 mm Normal force under each of the front tires: Nf= Normal force under each of the rear tires: N₁ = i i N N
The mass center G of the 1280-kg rear-engine car is located as shown in the figure. Determine the normal force under each tire when the car is in equilibrium. State any assumptions. Answers: -1320 mm-974 mm Normal force under each of the front tires: N₁= Normal force under each of the rear tires: N₁= N N
The mass center G of the 1295-kg rear-engine car is located as shown in the figure. Determine the normal force under each tire when the car is in equilibrium. State any assumptions. Answers: -1311 mm-910 mm Normal force under each of the front tires: N= Normal force under each of the rear tires: N,= N N
The mass center G of the 1455-kg rear-engine car is located as shown in the figure. Determine the normal force under each tire when the car is in equilibrium. State any assumptions. Answers: 1381 mm 996 mm Normal force under each of the front tires: N;= Normal force under each of the rear tires: N₁ = i i N -/10 I N
The cable AB prevents bar OA from rotating clockwise about the pivot O. If the cable tension is 680 N, determine the n- and t- components of this force acting on point A of the bar. TL B Answers: Tn= Tt= i Submit Answer Attempts: 0 of 1 used -1.9 m Save for Later 0 53° 2.4 m N N
The forces are in static equilibrium. The 140 lb force is directed along the x-axis and the 300 lb force is directed along the negative z-axis. What is the angle between R and the z-axis? Provide your answer in degrees, but do not include units in your answer. Z X R ex лог 140lb A 1-50, 80, 160) lb By 300 lb Y
The mass center of the 1255-kg rear-engine car is located as shown in the figure. Determine the normal force under each tire when the car is in equilibrium. State any assumptions. Answers: -1277 mm-875 mm Normal force under each of the front tires: M Normal force under each of the rear tires: N- i z z N N