The 208 V, two pole, 60 Hz. Y-connected wound rotor induction motor is rated for 15 hp. Equivalent The circuit components are: R1 0.200 Ω R2 = 0.120 Ω XM = 15.0 2 Χ1 = 0.410Ω X2 = 0.410Ω = Pmech - 250W Pmisc 0 Pcore = 180 W, For a shift of S=0.05 (a) Line current IL. (b) Stator copper losses PSCL. (c) Air gap power PAG. (d) Power converted from electrical to mechanical form Pconv. (e) Induced torque Tind. (f) Overall machine efficiency n. (g) Find the engine speed in revolutions per minute and in radians per second. Not: Please I want the answer step by step.

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter32: Three-phase Motors
Section: Chapter Questions
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The 208 V, two pole, 60 Hz. Y-connected wound rotor induction motor is rated
for 15 hp. Equivalent The circuit components are:
R1
0.200 Ω
R2 = 0.120 Ω
XM = 15.0 2
Χ1 = 0.410Ω
X2 = 0.410Ω
=
Pmech
-
250W Pmisc 0 Pcore = 180 W, For a shift of S=0.05
(a) Line current IL.
(b) Stator copper losses PSCL.
(c) Air gap power PAG.
(d) Power converted from electrical to mechanical form Pconv.
(e) Induced torque Tind.
(f) Overall machine efficiency n.
(g) Find the engine speed in revolutions per minute and in radians per second.
Not: Please I want the answer step by step.
Transcribed Image Text:The 208 V, two pole, 60 Hz. Y-connected wound rotor induction motor is rated for 15 hp. Equivalent The circuit components are: R1 0.200 Ω R2 = 0.120 Ω XM = 15.0 2 Χ1 = 0.410Ω X2 = 0.410Ω = Pmech - 250W Pmisc 0 Pcore = 180 W, For a shift of S=0.05 (a) Line current IL. (b) Stator copper losses PSCL. (c) Air gap power PAG. (d) Power converted from electrical to mechanical form Pconv. (e) Induced torque Tind. (f) Overall machine efficiency n. (g) Find the engine speed in revolutions per minute and in radians per second. Not: Please I want the answer step by step.
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The 208 V, two pole, 60 Hz. Y-connected wound rotor induction motor is rated
for 15 hp. Equivalent The circuit components are:
R1
0.200 Ω
R2 = 0.120 Ω
XM = 15.0 2
Χ1 = 0.410Ω
X2 = 0.410Ω
=
Pmech
-
250W Pmisc 0 Pcore = 180 W, For a shift of S=0.05
(a) Line current IL.
(b) Stator copper losses PSCL.
(c) Air gap power PAG.
(d) Power converted from electrical to mechanical form Pconv.
(e) Induced torque Tind.
(f) Overall machine efficiency n.
(g) Find the engine speed in revolutions per minute and in radians per second.
Not: Please I want the answer step by step.
Transcribed Image Text:The 208 V, two pole, 60 Hz. Y-connected wound rotor induction motor is rated for 15 hp. Equivalent The circuit components are: R1 0.200 Ω R2 = 0.120 Ω XM = 15.0 2 Χ1 = 0.410Ω X2 = 0.410Ω = Pmech - 250W Pmisc 0 Pcore = 180 W, For a shift of S=0.05 (a) Line current IL. (b) Stator copper losses PSCL. (c) Air gap power PAG. (d) Power converted from electrical to mechanical form Pconv. (e) Induced torque Tind. (f) Overall machine efficiency n. (g) Find the engine speed in revolutions per minute and in radians per second. Not: Please I want the answer step by step.
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