Temperature Conversions: 1. 0 °F= 2. 32 °F= 3. 68 °F= 4. 100 °F= 5. 212 °F= 11.0 °F= 12. 32 °F= 13 212 °F - °C °C °C °R °C °C °R op 6. 0°℃= 7. 25 °C= 8. 37 °C=_ 9. 50 °C= 10. 200 °C = 16.0 °C = 17.-50 °C = 10 100.8C °F °F °F °F K °F K

Elementary Algebra
17th Edition
ISBN:9780998625713
Author:Lynn Marecek, MaryAnne Anthony-Smith
Publisher:Lynn Marecek, MaryAnne Anthony-Smith
Chapter1: Foundations
Section1.10: Systems Of Measurement
Problem 1.308TI: Convert the Celsius temperature to degrees Fahrenheit: the temperature in Sydney, Australia, was 10º...
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More Temperature Conversion Exercises
Perform the following temperature conversions and place answers in the spaces
provided.
Temperature Conversions:
1. 0°F=
2. 32 °F=
3. 68 °F=
4. 100 °F=
5. 212 °F=
11.0°F=
12. 32 °F =
13. 212 °F =
14.450 °R =
15.632 °R =
°C
°C
°C
°R
°℃
°C
°R
°R
°F
°F
6. 0°℃=
7. 25 °C =
8.
37 °C =
9. 50 °C=
10. 200 °C =
Course Section/Date
16.0 °C =
17. -50 °C =
18. 100 °C =
19.400 K =
20. 50 K =
°F
°F
°F
°F
K
°F
K
K
°C
°C
Transcribed Image Text:Name More Temperature Conversion Exercises Perform the following temperature conversions and place answers in the spaces provided. Temperature Conversions: 1. 0°F= 2. 32 °F= 3. 68 °F= 4. 100 °F= 5. 212 °F= 11.0°F= 12. 32 °F = 13. 212 °F = 14.450 °R = 15.632 °R = °C °C °C °R °℃ °C °R °R °F °F 6. 0°℃= 7. 25 °C = 8. 37 °C = 9. 50 °C= 10. 200 °C = Course Section/Date 16.0 °C = 17. -50 °C = 18. 100 °C = 19.400 K = 20. 50 K = °F °F °F °F K °F K K °C °C
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