T1 12v 6v A 4.5v 3v To Diode circuit Ov common B D1 A C1 1000pF RL 1B4B42 3k0 ind the output voltage across the load RL VL output current through RL nd the power dissipated by RL for the following input voltages w4.5v,6v,9v & 12
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- What is CEMF?A clamper circuit has 20 Vp-p. 100Hz square wave input voltage. The circuit consists of silicon diode IN4001 and 3V battery as shown in Figure 1 C. 0.1 µF D R Vi(t) 50 k2 Vo(t) 3 V Figure 1 a) Find the output voltage for all input voltages values. b) Sketch the output waveform, Vo(t).The cut-in voltage for each diode in the circuits shown in Figure Pl.30 is V, = 0.6 V. For each circuit, determine the diode current I, and the voltage Vo (mea- sured with respect to ground potential). Q7 R= 10 k2 Vo oVo Ip R= 10 k2 5 V 5V 5 V 5 V (a) (b) R= 10 k2 Vo 5V E 5 V (c)
- Q4) Determine and sketch the output voltage across the load resistor (RL) for the circuit shown below. (assume Si diodes) V_DC 0.75 0.25 V_SIN Y SIN as RL -1 v SOR V_SQR 0.75 -0.75 V_TRI V TRI asVps = 10 V R = 0.1k02 ww -ovo R₁. Consider the Zener diode circuit shown in figure. The Zener diode voltage is Vz= 5.8V at Iz= 10mA and the Zener resistance is rz = 200. a) Find the output voltage for RL = 1k0 b) Find the change in the output voltage when the load resistance varies +ARL.For the circuit in the figure, let V input = 8V, Ri = 12ohms, RL = 10ohms, and VZ = 3.3V. Determine the voltages and currents of the resistors and the current of the zener diode.
- Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to IL-DC =0:5A RL VL-DC =20V 220V omsb O 001 F O 0.02 F O 0.0167F O None of the above ActivatePower supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V ams 5OHZ İL-DC =05A RL VL-DC =20VIn the clamping circuit below, assume the diode has Von-0.7V and V₁ is a sinusoidal wave with a peak-to-peak amplitude of 10V. How much is the maximum value of the output voltage signal (Vmax)? And how much will it be if we set V₂=2V? Input V1 C1 0.1e-6 9.3 V and 7.3 V 9.3 V and 11.3 V 11.3 V and 7.3 V O 7.3 V and 12.0 V O 12.0 V and 7.3 V Output D1 1N4148 .tran 30-3 V2 0 Vmax V(output) 0.0ms putput MAN Input 0.6ms 1.2ms V(input) 1.8ms 2.4ms 3.0ms
- V, is a 60Hz source with a peak voltage VP-120V is feeding a rectifier, assume ideal diode. The load resistance has a value of R= 10 k0. If ripple voltage Vr = 2V, the Diode average current Ipavg is VI Select one: a. + e. None Ob. 580mA Oc. 850mA Od 245mA 425mA D C: www tu Vo Q6After replacing R5 with diode IN4007 (switch K3 to diode side) .What conclusion can you draw from analysis of this step ?Questions 1 V, is a 60Hz source with a peak voltage VP-120V is feeding a rectifier, assume ideal diode. The load resistance has a value of R= 10 kn. If ripple voltage Vr = 2V, the Diode average current Ipavg is VI Select one: None b. 580mA 850mA O c. Od 245mA O e. 425mA D C C: R www Q+ Vo