t us assume you have built a CNN with following details - It consists of three convolutional layers, each with 3 x 3 kernels, a stride of 2, and SAME padding. o The first layer outputs 100 feature maps o The second layer outputs 200 feature maps o The third layer outputs 400 feature maps The input images are RGB images of 720 x 1280 pixels.

t us assume you have built a CNN with following details - It consists of three convolutional layers, each with 3 x 3 kernels, a stride of 2, and SAME padding. o The first layer outputs 100 feature maps o The second layer outputs 200 feature maps o The third layer outputs 400 feature maps The input images are RGB images of 720 x 1280 pixels.

Microsoft Visual C#

7th Edition

ISBN:9781337102100

Author:Joyce, Farrell.

Publisher:Joyce, Farrell.

Chapter8: Advanced Method Concepts

Section: Chapter Questions

Problem 7RQ

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In MATLAB, a grey-scale image is stored a a matrix of numbers, all between 0 (black) and 255 (white). Since there are 256 possible values, 8 bits are needed or each pixel, in contrast to a normal integer, which is 64 bits.To save memory, grey-scale images are stored with a special data type, uint8 (unsigned 8-bit integer). In computer terminology, 8 bits = 1 byte. Even at one byte per pixel, a large image can consume a lot of memory. For example, a 1000x1000-pixel image takes 1 million bytes (which is a little less than 1 megabyte, since by convention 1 Mbyte = 2^20 bytes). One technique for reducing the size of an image is quantization - reducing the number of allowable levels from 256 to something smaller. Surprisingly, most images can be quantized by a large factor without losing much information. In this problem, you will quantize a grey-scale image to only 4 levels, so that it could (in principle) be stored as 2 bits per pixel. The template will read in an image file. Your job…
Computer Science Let us assume you have built a CNN with following details - It consists of three convolutional layers, each with 3 x 3 kernels, a stride of 2, and SAME padding. o The first layer outputs 100 feature maps o The second layer outputs 200 feature maps o The third layer outputs 400 feature maps The input images are RGB images of 720 x 1280 pixels. Q. What is the minimum total RAM needed if parameters are stored in 32-bit floats. Assume making prediction for a single image.
Let A and B be two vectors of length n. The first element of vector A is stored at location LOCA and the first element of vector B is stored at location LOCB. The length n is stored at location N. Write a RISC-style program to perform the vector addition and storing the result starting the memory location VECSUM.
Load infile using one byte per channel and save it as a PNG, using outfile for the file name. Use one byte per channel. graphics.cpp 1 #define STB IMAGE IMPLEMENTATION 2 #define STB IMAGE WRITE IMPLEMENTATION #include "stb_image.h" #include "stb_image_write.h" 3 4 #include #include 7 using namespace std; 8 9. int main() 10 { string infile = "pete.png"; string outfile = "out.png"; 11 12 13 14 15 16 17 } CodeCheck Reset
2. The computer in mars has a fivenary memory - that is each location can hold a frit value, with a frit holding 0, 1, 2, 3, or 4. How many frits are needed to hold a 6-octal_bit number. Give an expression for the number of frits to hold n octal bits.
Suppose a color monitor has a 1920x1080 frame size and uses 8 bits for each of the three primary colors per pixel. What is the minimum size in bytes of the frame buffer to store a frame? Enter only the final answer with no commas.
An application loads 100 libraries at start-up. Loading each library requires exactly one disk access. The seek time of the disk to a random location is given as 10 ms. Rotational speed of disk is 6000 rpm. If all 100 libraries are loaded from random locations on the disk, how long does it take to load all libraries? (The time to transfer data from the disk block once the head has been positioned at the start of the block may be neglected.)
Consider a color image with 6x8 pixels. R, G, and B components are stored with 8 bits. There are 2^n distinct colors in the image and each pixel is stored with n bits in index color format. What is the MAXIMUM value of n that makes index color format more advantageous than RGB color format?
Create a program in C++ which simulates a direct cache. The memory array that contains the data to becached is byte addressable and can contain 256 single byte entries or lines. The cache has only 8 entriesor lines. The Data field in each line of the cache is 8 bits. Since the data stored in each line of the cache isonly 8 bits, there is no need for a line field. Only a tag field is needed which is log2(256) = 8 bits.The memory array can be filled with any values of your choice. The program should work by taking userinput of a memory address (index). This input represents the memory data that should be cached.Check the cache to see if the item is already cached. If it is not, your program should counta cache miss, and then replace the item currently in the cache with the data from the inputted address.Allow the user to input addresses (in a loop), until they so choose to end the program. The program should output the number of cache misses upon ending.
You are writing a new 3D game that you hope will earn you fame andfortune. You are currently working on a function to blank the screenbuffer before drawing the next frame. The screen you are working withis a 640 × 480 array of pixels. The machine you are working on has a64 KB direct-mapped cache with 4-byte lines. The C structures youare using are as follows:1 struct pixel {2 char r;3 char g;4 char b;5 char a;6 };78 struct pixel buffer[480][640];9 int i, j;10 char *cptr;11 int *iptr;Assume the following:sizeof(char) = 1 and sizeof(int) = 4.buffer begins at memory address 0.The cache is initially empty.The only memory accesses are to the entries of the array buffer.Variables i, j, cptr , and iptr are stored in registers.What percentage of writes in the following code will miss in the cache?1 for (j = 0; j < 640; j++) {2 for (i = 0; i < 480; i++){3 buffer[i][j].r = 0;4 buffer[i][j].g = 0;5 buffer[i][j].b = 0;6 buffer[i][j].a = 0;7 }8 }
Create a program in C++ which simulates a direct cache. The memory array that contains the data to be cached is byte addressable and can contain 256 single byte entries or lines. The cache has only 8 entries or lines. The Data field in each line of the cache is 8 bits. Since the data stored in each line of the cache is only 8 bits, there is no need for a line field. Only a tag field is needed which is log2(256) = 8 bits. The memory array can be filled with any values of your choice. The program should work by taking user input of a memory address (index). This input represents the memory data that should be cached. Your program will check the cache to see if the item is already cached. If it is not, your program should count a cache miss, and then replace the item currently in the cache with the data from the inputted address. Allow the user to input addresses (in a loop), until they so choose to end the program. The program should output the number of cache misses upon ending.
Connect a 5*7 dot-matrix display to the 8051-microcontroller (Draw the schematic on paper). Then, display the content of variable NUMBER on the display, digit by digit every one second. for example if NUMBER=249, then "2" will be displayed for one second, after that digit "4" and finally digit "9" will be displayed for a whole second. Assume that the necessary lookup table exists in Memory at address OXF000.