SW 4 SW 3 SW 2 SW 1 column. A ооооо -● 0 0 0 1 1 1 1 1 1 1 1 B ● D A (SW4) 2 Apply the inputs shown in Table 38 9 10 0 0 0 0 1 1 1. 1 0 0 0 0 1 1 1 1 B (SW3) tep 6. Output expression: F = LO 5 6 INPUTS 0 0 and record the output state in the right hand. C (SW2) D (SW1) 0 0 1 1 4 0 1 1 0 0 1 1 F 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 L1 OUTPUTS F (L1) Fig. 4-2
SW 4 SW 3 SW 2 SW 1 column. A ооооо -● 0 0 0 1 1 1 1 1 1 1 1 B ● D A (SW4) 2 Apply the inputs shown in Table 38 9 10 0 0 0 0 1 1 1. 1 0 0 0 0 1 1 1 1 B (SW3) tep 6. Output expression: F = LO 5 6 INPUTS 0 0 and record the output state in the right hand. C (SW2) D (SW1) 0 0 1 1 4 0 1 1 0 0 1 1 F 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 L1 OUTPUTS F (L1) Fig. 4-2
Programming Logic & Design Comprehensive
9th Edition
ISBN:9781337669405
Author:FARRELL
Publisher:FARRELL
Chapter5: Looping
Section: Chapter Questions
Problem 4PE
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