Suppose that the S allele in a population of organisms is present at an 80 percent frequency, and the s allele at a 20 percent frequency. After individuals in one generation mate randomly what will be the frequency of heterozygotes?
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- CH 1-4 X ← → C Maya X Credibi X app.wizer.me/learn/00E0A8 wizer.TIE a Maya S x BW x BW To-do X Assign x b M Dashb X BB x BW Figura X Figurat X A chicken breeder has chickens that are white, black, or speckled. Speckled chickens have both black and white feathers. The allele for white feathers is (W). The allele for black feathers is (B). Determine the genotypes of the rooster and hen that would breed the greatest percentage of speckled chickens. BW x WW Dashboard Incomp X Interac X STILCI GIESS LUUC BB x WW + with white (W). The heterozygous phenotype is brown and white V < ☆ GO#4: Ch. 20- Hardy-Weinberg The ApoE gene has three common alleles: E2, E3 and E4. A population survey of Reno reveals the following frequencies: 0.10 for E2, 0.15 for E3, 0.75 for E4. Assume random mating is occurring. If the E4 allele confers resistance to hepatitis C (when 1 or 2 copies are present), what proportion of the population is NOT resistant to hepatitis C? Kidd S'07Imagine a population 528 individual plants. In this population, 4 % of the plants produce red flowers, and 9 % produce pink flowers. The remaining plants produce white flowers. Flower colour is attributed to a single locus with two alleles. Red flowers are produced by plants that are homozygote for the R allele. White flowers are produced by plants that are homozygote for the W allele. Heterozygotes (RW) produce pink flowers. What is the expected (under Hardy-Weinberg equilibrium) number plants producing pink flowers in this population? Round your answer to the closest full number.
- A.) Assuming there is random mating, find the gene frequencies, genotypic frequencies, and the proportion of individuals with the different blood types (Type A, B, AB and O) if the population is composed of the following: Туре А - 80 Туре АВ - 35 Туре В - 90 Type o - 195 Type O = 195/400 = 0.488 Type A = 80/400 = 0.200 Type AB = 35/400 = 0.087 Type B = 90/400 = 0.225 Gene frequency: Genotypic frequency: f(0)= r=r2 =0.4882 f(AA) = p2=0.22 f(AA)=0.04 f(0)=r= 0.488 f(AO) =2pr =2(0.2)(0.488) =0.195 E(A)=p=1-(g+r) f(BB) = q2 =0.4882=0.238 =1-(0.225+0.488) f(BO) =2qr=2(0.225)(0.488)=0.220 f(A)=p =0.287 f(AB)=2pq=2(0.200)(0.488)=0.195 f(o0)=r2=0.4882=0.488 f(B)=q=1-(p+r) f(B)=q=1-(0.200+0.488) f(B)=q=0.312 Proportion: 1.) TYPE A = AA+AO 4.) TYPE O = 00 (p2+2pr) x total=(0.04+0.195) x 400 = 94 (r2) x total=(0.488) x 400 = 195.2 2.) TYPE B = BB+BO (q2+2qr) x total=(0.238+0.220) x 400 = 183.2 3.) TYPE AB = AB (2pq) x total=(0.195) x 400 = 78Imagine a locus with two alleles. Mutation at this locus changes one allele to the other (i.e. it does not create a new allele). If the rate of mutation from allele 1 to allele 2 is 0.00005 and the rate of mutation from allele 2 to allele 1 is 0.01, what is the equilibrium frequency of allele 2 (Give your answer to 5 decimal places)?Individuals with genotype A have a lifetime reproductive success of 4. Individuals with genotype B have a lifetime reproductive success of 2. What is the relative fitness of genotype A?
- A population consists of 300 individuals with the following genotypes: AA – 100 Aa – 125 aa – 75 For the population in the problem above, imagine that the homozygous recessives are deleterious and that only 80% of these individuals survive to reproduce. If the other genotypes have a 100 % survival rate, and in each surviving individual replaces itself through reproduction, what are the values of p and q after one generation?p + q = 1 p2 + 2pq + q2 = 1 p is the frequency of the dominant allele q is the frequency of the recessive allele p2 is the frequency of homozygous dominant genotype q2 is the frequency of homozygous recessive genotype 2pq is the frequency of heterozygous genotype Within a population of roses, the color red (R) is dominant over the color white (r). 40% of all the roses are white.a)The percentage of roses in the population that are heterozygous b) The frequency of homozygous dominant individuals =The agouti gene determines coat colour in mice. Heterozygous mice have yellow coats, while homozygous dominant mice have black coats. However, having two copies of the recessive alleles is lethal. In a population of 2 000 mice, 1 082 mice have black coats. a) Calculate the frequency of each allele. Show all your work and express your answer as a value between 0 and 1 rounded to two decimal places. b) What percentage of the mouse population is expected to be carriers of the lethal allele? Show all your work and express your answer rounded to one decimal place. c) How many mice will die during fetal development? Show all your work and round your answer to the closest whole number.
- 75. Under the conditions of the Hardy-Weinberg equilibrium, what term in the equilibrium equation represents the expected genotype frequency for homozygous recessive individuals? p2 2pq 2p+q p2+2pq+q2 q2A population of rabbits may be brown (the dominant phenotype) or white (the recessive phenotype). Brown rabbits have the genotype BB or Bb. White rabbits have the genotype bb. The frequency of the BB genotypre is .35 What is the frequency of the heterozygous rabbits? What is the frequency of the B allele? What is the frequency of the b allele?A scientist is studying a wild population of Japanese morning glories. It is easy to separate genotypes at a flower color locus by their phenotypes. Red individuals are homozygous for the R allele, yellow individuals are homozygous for the Y allele, and orange individuals are heterozygous. If the number of individuals with the following genotypes are: RR: 831 RY: 33 YY: 442 Is the population in Hardy Weinberg Equilibrium?