Suppose that the population P(t) of a country satisfies the differential equation = kP(900 – P) with k constant. Its population in 1960 was 300 million and was then growing at the rate of 2 million per year. Predict this country's population for the year 2010. This country's population in 2010 will be million.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
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Suppose that the population P(t) of a country satisfies the differential equation
dP
= kP(900 – P) with k constant. Its population in 1960 was 300 million and was then growing at the
dt
rate of 2 million per year. Predict this country's population for the year 2010.
This country's population in 2010 will be
million.
(Type an integer or decimal rounded to one decimal place as needed.)
Transcribed Image Text:Suppose that the population P(t) of a country satisfies the differential equation dP = kP(900 – P) with k constant. Its population in 1960 was 300 million and was then growing at the dt rate of 2 million per year. Predict this country's population for the year 2010. This country's population in 2010 will be million. (Type an integer or decimal rounded to one decimal place as needed.)
Expert Solution
Step 1

Assume 1960 is the starting year and the population, P is in millions.

So, at t=0 the value of P will be 300.

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