Suppose an application programmer was supposed to write a query select * from r natural left outer join s; on relations r(A, B) and s(B, C), but instead wrote the query select * from r natural join s; a. Give sample data for r and s on which both queries would give the same result. b. Give sample data for r and s where the two queries would give different results, thereby exposing the error in the query.
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Suppose an application programmer was supposed to write a query
select *
from r natural left outer join s;
on relations r(A, B) and s(B, C), but instead wrote the query
select *
from r natural join s;
a. Give sample data for r and s on which both queries would give the same
result.
b. Give sample data for r and s where the two queries would give different
results, thereby exposing the error in the query.
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- What does an EXCEPT (MINUS) query care about operand order, while a UNION query doesn't?Given the tables create table T (A int primary key, B int); create table U (C int primary key, A int, foreign key(A) references T(A) ); Table T contains 100 rows and table U contains 200 rows. A common mistake made by students is to do a join and assuming the database will supply the join predicate. A student does the query SELECT T.A, T.B, U.C FROM T, U; The student does not get an error message but gets a large result set. How many rows are in the result set?SQL Use appropriate clauses and filters to run the query with minimum time complexity. 2. Try to avoid running the queries on unnecessary rows and columns. 3. Share the queries along with a brief description of the code in a python file, so that the results are reproducible. Q1: Write a query to find the students working in a company having more ratings than their seniors EMPLOYEES RATING TABLE student id student name rating senior id designation 1 george 9 3 student 2 micheal 8 4 student 3 mary 6 null senior 4 steve 9 null senior For the above table GEORGE has more rating than his sENIOR
- 1. Create a PL/SQL function. The minimal requirements: using the cursor in PLSQL function, retrieve data from object table and record the data in the PL/SQL table, make calculations with object data and define return value of the function, test the operation of the function (get the result). The maximal requirements: you can add IF-ELSEIF's, cursor processing in loops, more interesting semantic functions. 2. Create methods for object types. The minimal requirements: use map/order methods (1 method) (method+ demonstration), use MEMBER methods (2 methods) (methods + demonstration). The maximal requirements: non-trivial methods, that use more complex comparisons or do more complex calculations – i.e., give a couple more constructs in code. 3. Demonstrate the multiset operators. The minimal requirements: using 2 different multiset operators (can be included in the code), they can also be used in the The maximal requirements: the queries make sense semantically, one of the queries is a…1. Write a PL/SQL program using an explicit cursor that displays all patients PLCO_ID numbers from the colo_proc_data table on the screen if the patients’ procedure is biopsy, the procedure is staging, interval status of linked cancer is never screened, the procedure type is invasive Scopes, biopsies, & surgeries, the procedure type is Lymphadenectomy/Lymph Node Sampling, and the procedure result is abnormal, confirmed metastasis.SQL: Create a SQL query that uses an uncorrelated subquery and no joins to display the descriptions for products provided by a vendor in area code 615. Remember, the main difference between a correlated subquery and uncorrelated subquery is that, in a correlated subquery, the inner query is dependent upon the outer query, while, with an uncorrelated query, the inner query does not depend upon the outer query. Instead, it runs just once. You should NOT use union, minus, or intersect in this query. The outer query will use the PRODUCT table and the inner query will use the VENDOR table [hint: you should have 9 records of output]. My code: select p_descript from product where (select v_areacode from vendor where v_areacode = '615' ; I am getting this error, problem is I can't see what is missing any assistance is appreciated. ORA-00936: missing expression
- Develop a PL/SQL block that would go through all the employees from EMPLOYEES table who work in department id= 90 (there is suppose to be 3 employee who work in Department 90)- IN BEGIN END END SECTION; Execute 3 separate of SELECT statement one after the other. Each SELECT will pull first name. salary of each employee and store them in local variables.+ SELECT LOAD INTO v_firstname1, v_salarxlWHERE emrlexee.id=100 Then second WHERE emploxee.id3101+ SELECT first_name, salary INTO v_firstname2, v_salary2 Then third + SELECTSELECTI tirst.name, salary INTO v_firstname3, v_salary3 iin WHERE emploxee id=102 ..... You must now have 6 local variables. DECLARE all of them accordingly in DECLARE section and use them in BEGIN and END.+ Then add another SELECT statement in BEGIN-END to find company average salary SELECT xa(salary) INTO aKasal FROM EMPLOYEES; !!! Do not forget to create y avgsal local variable in DECLARE section.Consider tables S (A, B, C) and T (B, C, D) and SQL query select A, B, C, D from S, T where S.B = T.B and S.C = T.C Design a MapReduce program to compute the join efficiently. Please provide the pseudocode.Write a PL/SQL Function that accepts 4 integers, 2 representing the homeTeamID and visitorTeamID, and the other 2 representing the score for each team during a game : htscore and vtscore The function will determine which team won the match and return the teamID of the winning team. You can achive this by comparing htscore > or < then vtscore.. if htscore is bigger then return hteamID or else return vteamID. If the game was a tie (the 2 scores are the same value) return a 0.
- PLZ help with the following: IN SQL Let R (A, B, C) be a relation schema. What happens if we execute the following query? SELECT* FROM R WHERE A=D; Select one: a. We get an error. b. The query executes successfully but returns no tuples. c. The query returns all the tuples in R.The following SQL queries use the instances of R1 of "Reserves" the instances of B1 of "Boats", and the instances of S1 of "Sailors" relation. An instance R1 of Reserves bid 101 103 103 day 10/10/96 11/12/96 10/11/96 12/01/96 12/05/96 10/10/09 10/10/98 104 10/07/98 11/10/98 09/08/98 09/05/98 09/08/98 SIC 22 22 31 31 22 22 31 64 64 74 103 102 104 102 101 102 103 An instance B1 of Boats bid 101 102 103 bname Interlake Interlake Clipper Marine 104 bcolor blue red green red An instance S2 of Sailors SIG 28 31 21 44 26 58 22 22 29 29 22 32 2 64 21 74 85 95 71 sname yuppy Tubber guppy rusty Dustin Brutus Andy Horte Horatio Zorba Art Bob Amy rating 81 5 10 11 1 & |10|| El 3 115 age 35 155 135 135 45 33 25 135 18 25 635 46 1.If we wish to list out only the names and ratings of the sailors, we can write this in SQL statement as 2.Find out only the names and ages of sailors. 3.To find out the names and ratings of sailors with a rating above 8, we can combine two of the preceding queries as:…Consider tables S (A, B, C) and T (B, C, D) and SQL query select A, B, C, D from S, T where S.B = T.B and S.C = T.C Design a MapReduce program to compute the join efficiently. Please provide the pseudocode.