5. Suppose a kite string of radius 2.00 mm extends directly upward by 0.800 km and is coated with a 0.500 mm layer ofwater having resistivity 150 Q.m. If the potential difference between the two ends of the string is 160 Mv, what is thecurrent through the water layer?

To find the current through the water layer we need to find the resistance of the water layer.…

Suppose a kite string of radius 2.00 mm extends directly upward by 0.800 km and is coated with a 0.500 mm layer of water having resistivity 150 2.m. If the potential difference between the two ends of the string is 160 Mv, what is the current through the water layer?

Suppose a kite string of radius 2.00 mm extends directly upward by 0.800 km and is coated with a 0.500 mm layer of water having resistivity 150 2.m. If the potential difference between the two ends of the string is 160 Mv, what is the current through the water layer?

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter20: Electric Current, Resistance, And Ohm's Law

Section: Chapter Questions

Problem 13PE: A large cyclotron directs a beam of He ++ nuclei onto a target with a beam current of 0.250 mA. (a)...

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Concept explainers

Resistivity

Resistivity is a characteristic property of the conductor’s material that measures the extent to which the material opposes the flow of current. It is denoted by the Greek letter “rho”. Electrical resistivity, also known as specific resistance, depends on the nature of the material of the conductor and is unaffected by its dimensions.

Question

5. Suppose a kite string of radius 2.00 mm extends directly upward by 0.800 km and is coated with a 0.500 mm layer of
water having resistivity 150 Q.m. If the potential difference between the two ends of the string is 160 Mv, what is the
current through the water layer?

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