Suppose a 500. mL flask is filled with 1.8 mol of Cl₂ and 1.3 mol of HCl. The H₂(g) + Cl₂(g) 2HCl(g) L The equilibrium constant K for this reaction is 6.75 at the temperature of the flask. Calculate the equilibrium molarity of Cl₂. Round your answer to two decimal places.
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- Analysis of dissolved sulfate concentration is based on the precipitation reaction of barium sulfate, creating Baso4 5) (named barite) and its settling. The following water quality is given: TDS = 650 mg/I, (SO) = 40 mg/l as S. Solubility constant of BaSO:: Kip (Baso.) = 1.1 1010 Determine how many mg of BaCl, should be added to 200 ml of a solution at the given quality for completely precipitating the sulfate. That is, calculate the dose required for 99.9% removal, while assuming saturation with respect to barite is immediately reached.cula... = 18.3 Gibbs Free E... O Kinetics and Equilibrium Calculating equilibrium composition from an equilibrium constant Suppose a 500. mL flask is filled with 0.10 mol of Cl₂ and 0.50 mol of HCI. The following reaction becomes possible: H₂(g) + Cl₂(g) -2HCl(g) M 18.3 Gibbs Free E... The equilibrium constant K for this reaction is 0.204 at the temperature of the flask. Calculate the equilibrium molarity of Cl₂. Round your answer to two decimal places. Explanation DEC 10 Check 5.3 Enthalpies of... CP 18.5 Gibbs Free E... X tv Nall © 2023 McGraw Hill LLC. All Rights Resea ADetermine the value of the equilibrium constant, Kgoal, for the reaction N2(g) + O2(g) + H2 (g) = ;N¿H4(g)+NO2(g), : ? by making use of the following information: 1. N2 (g) + O2 (g): = 2NO(g), K1 4.10 x 10-31 2. N2 (g) + 2H2 (g) = - N2H4(g), K2 7.40 x 10–26 3. 2NO(g) + O2 (g) = 2NO2(g), K3 = 6.00 x 10-13 Express your answer numerically. • View Available Hint(s) Vo AEO ? Kgoal =
- Non-Commercial Substances Hypothesis: Soluble in Test Bond Molecular Structure ΔΕΝ H2O? Result: H20 Solubility Result: Hexane Substance Classification Solubility Hexane? H2O: pS Sodium Na--Br lonic Bromide 1.9 Hexane: I |--| lodine NP C 0.0 Ammonium N/A lonic Carbonate NH4* O O NH4* Sodium N/A lonic Acetate C--H NP C 0.4 H-C-OH C--O PC H-C-OH Glycerol 1.0 H-C-OH O--H PC 1.4 HICalculate the molar solubility of tin(II) hydroxide (Ksp = 5.45x10-27). Give your answer to three sig. figs. and in exponential form (e. g. 1.23E-2).we dissdve 350ml volumetric Flask.LWe call this sdlution (S) oa of hydrated cupric sulfate (cusoy.5H,0 in given.molar mass launol ). Cu:64 S-32 H+ 1 1. Write the equation of dirsociation of hydrated cupric sulfate in water. 12. Calculate the molar mass of hydrated cupric sulfate. 1.3. Determine the molar concentration of (S). 14. Deduce it's mass concentiation. 1.5.1ist te materials used. 16. Write the procedure of preparting (5).
- :41 AM Mon Feb 27 S Given the generic reaction, T ... Systems in Chemical Equilibrium I A(aq) + B(aq) → C(aq) 1. Write the mass action expression for Kc, the equilibrium constant. Kc = [Products] [reactants] Kc = Q Name: Hailey GAY equilibrium shift to counteract the disturbance? Backward [A][B] Ace MASS Actions 109 librium and then A was removed which direction would the equilibrium Stift to counteract the distors If the system above was at equilibrium and then a List at least two ways that you could Omonen Shirt to counteract the disturbance?for ACE oper @ 100% +: 0 direction would the 2.400 more reactant, &09) In 6. If the temperature of the equilibrium system above is decreased and the concentrations of the reactants A and B decrease, then is the "heat" considered a reactant or product? a. Therefore from left to right, is the reaction endothermic or exothermic? b. What will happen to the value of Kc with the increase in temperature? Increase, decrease or remain constant?C www-awu.aleks.com/alekscgi/x/lsl.exe/10_u-IgNslkr7j8P3jH-IvTqeviKFP6W0cqJcWJdIACROQwyw24GWHInrCnyqVCaf_xSaZNy Solubility and... 18.5 Gibbs Free E... esc ||| 18.3 Gibbs Free E... OKINETICS AND EQUILIBRIUM Calculating equilibrium composition from an equilibrium constant M Explanation Suppose a 500. mL flask is filled with 1.4 mol of NO3 and 1.5 mol of NO₂. The following reaction becomes possible: NO₂(g) + NO(g) 2NO₂(g) The equilibrium constant K for this reaction is 3.89 at the temperature of the flask. Calculate the equilibrium molarity of NO₂. Round your answer to two decimal places. @ 2 5.3 Enthalpies of... Check W # 3 X E 10 54 $ S > R C % 5 e T Reading Schedule tv MacBook Pro ^ 6 & 19.6 Reduction Po... SOLUTI 7 Ⓒ2022 McGraw Hill LLC. All Rights Reser U * 00 8www-awu.aleks.com/alekscgi/x/lsl.exe/10_u-IgNslkr7j8P3jH-lvTqeviKFP6W0cqJcWJdIACROQwyw24GWHinwgLxrTA3qJGX 18.5 Gibbs Free E... Reading Schedule 4 Solubility and... esc 18.3 Gibbs Free E... 5.3 Enthalpies of.... O KINETICS AND EQUILIBRIUM Calculating equilibrium composition from an equilibrium constant Zoom (2).pkg Suppose a 250. mL flask is filled with 1.2 mol of Cl₂ and 0.60 mol of HCl. The following reaction becomes possible: H₂(g) + Cl₂(g). 2HCl(g) The equilibrium constant K for this reaction is 0.409 at the temperature of the flask. Calculate the equilibrium molarity of H₂. Round your answer to two decimal places. M Explcnation Check 3 X $ 4 S > C % 5 (Q) tv I A 6 We 19.6 Reduction Po... Ya sc & C Ⓒ2022 McGraw Hill LLC. All Rights You 9
- 1. The equilibrium constant of the reaction 2 C3H5 (g) = C2H4 (g) + C4H8 (g) is found to fit the expression ln K = - 1.04 - (1088 / T) + (1.51 x 105 / T^2 ) between 300 K and 600 K. Calculate the standard reaction enthalpy and standard reaction entropy at 400 K. [2.77 kJ mol-1 ; -16.5 kJ K-1 mol-1 ]-awu.aleks.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-IvTqeviKFP6W0cqJcWJdIACROQwyw24GWHinnFt 5.3 Enthalpies of... 18.5 Gibbs Free E... 18.3 Gibbs Free E... 21,108 M O ELECTROCHEMISTRY Ranking the strength of oxidizing and reducing agents using... species Use the information in the ALEKS Data tab to sort the following chemical species by reducing power. Ag(s) Ca'(s) Br (aq) Na(s) Explanation X Check reducing power DEC 5 choose one choose one choose one ✓ choose one S Reading Schedule tv CP 19.6 Reduction Ⓒ2022 McGraw H (A) MacBook Proow-owl.cengagenow.com/ilrn/takeAssignment/ta... OWLv2 | Assignmen... I Labflow - Course: U... At a particular temperature a 2.00-L flask at equilibrium contains 5.10 x 10-4 moles of N₂, 2.50 × 10-5 moles of 02 and 2.00 x 10-2 moles of N₂O. Calculate K at this temperature for the reaction 2N₂(g) + O₂(g) ⇒ 2N₂O(g) Submit Answer [References] K = If [N₂] = 2.00 × 10-4 M, [N₂O] = 0.200 M, and [0₂] = 0.00813 M, does this represent a system at equilibrium? 6 item attempts remaining M Inbox (2,487) Try Another Version