Süppose 10 mol HCIO4 (perchloric acid, a very strong acid) is dissolved in 1000 L of water. This gives (H*) = (10-6 mol)/(1000 L) = 10-9 M. Finally, the pH is calculated: pH = -log 10[H*] = -log10( 10 °) = 9.0, which corresponds to an alkaline solution! What is wrong?

Chemistry by OpenStax (2015-05-04)
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Chapter14: Acid-base Equilibria
Section: Chapter Questions
Problem 62E: For which of the following solutions must we consider the ionization of water when calculating the...
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3. Suppose 10-6 mol HCIO4 (perchloric acid, a very strong acid) is dissolved in 1000 L of water. This gives (H°] =
(10-6 mol)/(1000 L) = 10-9 M. Finally, the pH is calculated: pH = -logro[H*]= -log-o{10 °) = 9.0, which corresponds
to an alkaline solution! What is wrong?
%3D
%3D
!!
!3!
4. Calculate the pH of a 0.15 M solution of acetic acid, CH;COOH (K. = 1.8 x 109).
Transcribed Image Text:3. Suppose 10-6 mol HCIO4 (perchloric acid, a very strong acid) is dissolved in 1000 L of water. This gives (H°] = (10-6 mol)/(1000 L) = 10-9 M. Finally, the pH is calculated: pH = -logro[H*]= -log-o{10 °) = 9.0, which corresponds to an alkaline solution! What is wrong? %3D %3D !! !3! 4. Calculate the pH of a 0.15 M solution of acetic acid, CH;COOH (K. = 1.8 x 109).
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