Suggest reasons why RAMS traditionally have been organized as only 1 bit per chip whereas ROMs are usually organized with multiple bits per chip.
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A: The above question is solved in step 2 :-
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- how many address lines woukd a ROM have to have to hold 400 twos complement integers that could vary from -400 to +400?Addressing Memory Please answer D - E - F Suppose that there are 226 bytes in memory. In binary the lowest address is 00...00, and the highest address is 11...11. a. What is the lowest address (in decimal) if memory is byte addressable? b. What is the highest address (in decimal) if memory is byte addressable? c. Suppose that a word is 16-bits long. What is the lowest address (in decimal) if memory is word addressable? d. Suppose that a word is 16-bits long. What is the highest address (in decimal) if memory is word addressable? e. Suppose that a word is 32-bits long. What is the lowest address (in decimal) if memory is word addressable? f. Suppose that a word is 32-bits long. What is the highest address (in decimal) if memory is word addressable?متحكمات دقيقه نظري The ROM memory address of the PIC18F2410, 16KB: Select one: a. (0000-3FFF)H b. (0000-4000)H C. (0001-3FFF)H d. (0001-4000)H Previous page Nex search
- Suppose a CPU has 4 data pins. How many operations will it take to read a 32-bit word? Please show your solution.To the best of your ability, calculate the minimal number of bits required in the MAR for each of the following memory sizes. What is the real number of memory cells in a 640 KB memory unit that is claimed to have 640 KB? What do you think about 512 MB of RAM? What do you think about 2 GB of RAM? Explain the role that read-only memory (ROM) plays in the architecture of a computer system and why it is used. What kind of information is stored in read-only memory (ROM), and how does that information get into the memory in the first place?Write an 8085 microprocessor program to calculate the number of negative data among the following data (D4, 5E, 14, 93, 80, 11, 21, EE, 5D, 23, F1, C4, 39, 79, 10, OD). Note that D7 bit represents the sign, where 1 is for negative and 0 for positive.
- By assuming that X = 3, and 33 is a two digit number, consider memory storage of a 64-bit word stored at memory word 33 in a byte-addressable memory (a) What is the byte address of memory word 33? (b) What are the byte addresses that memory word 33 spans? (c) Draw the number 0xF1234567890ABCDE stored at word 33 in both big endian and little-endian machines. Clearly label the byte address corresponding to each data byte value.QUESTION 21 Give the maximum hex value that can be brought into the CPU at a time for a 20-bit data bus. FFFFH FFFFFH FFH FFFFFFHReversible operations with XOR:Often it is nice to be able to invert the bits in a value in a way that they are easily translated back to the original value. Inverting the bits and restoring them shows a assembly program to implement it. One use of this is to swap two values without using a temporary storage space.
- Show how the decimal value 2019111310 would be stored by byte-addressable machines with 32-bit words, using little endian format and then big endian format. Assume the value starts at address 201916. Draw a diagram of memory and place the appropriate values in the correct (and labeled) memory locations.physcal addresses are 4s ng 4 Ame dat in a cetain compe, te addresses can be translaled without y TLB entries At most how many ditina vid the address translation peh has 12 vld The Translation Look aside Bulfer (TLB)i sine is kB and the word size iby The memory is word addresible. The pe virtual addresses are 64 bea long d th sine is miss?you try to make binary multiplier using ROM which multiply two 4bit binary and result is binary ex: ____(2) * ____(2)=______(2) show ROM's volume and represent in block diagram (present every input,output with bits)