stoichiometric point, what is the molarity of the acetic acid (CH³CO₂H) in the vinegar? CH3CO₂H+ NaOH → H₂O+CH₂CO₂Na 0.30 M 0.600 M 0.300 M 0.60 M

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter16: Reactions Between Acids And Bases
Section: Chapter Questions
Problem 16.77QE
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A 20.00 mL sample of vinegar was titrated with 1.00 M NaOH. If it took 6.00 mL of NaOH to reach the equivalence or
stoichiometric point, what is the molarity of the acetic acid (CH₂CO₂H) in the vinegar?
CH₂CO₂H + NaOH → H₂O+CH₂CO₂Na
O
0.30 M
0.600 M
0.300 M
0.60 M
Transcribed Image Text:A 20.00 mL sample of vinegar was titrated with 1.00 M NaOH. If it took 6.00 mL of NaOH to reach the equivalence or stoichiometric point, what is the molarity of the acetic acid (CH₂CO₂H) in the vinegar? CH₂CO₂H + NaOH → H₂O+CH₂CO₂Na O 0.30 M 0.600 M 0.300 M 0.60 M
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