Step 2 9.5 m)+(55 m/s) t+ t + 0. When the players are side by side, Xplayer Xopponent- Equating the right-hand sides of the two equations from the previous step, we have (0 0.13 ✔ m/s²) 1² = 1 9.5 ✔ m/s) t When we simplify into the quadratic form at2 + bt + c = 0 where a = 1, we have the following quadratic equation in the variable t. Remember to pay attention to the signs and constant when entering the answers.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 53P: A surveyor measures the distance across a straight river by the following method: starting directly...
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need help converting to a quadratic formula

and
= 0 + 0 +
1/2/(
2
0.13
Xopponent (xo)opponent + (vo)opponent t +
0.13
0.13 m/s²t²
9.5✔ 9.5 m) + (5
✔ m/s²) t² = (
5✔
9.5
opponent
Step 2
When the players are side by side, Xplayer = Xopponent. Equating the right-hand sides of the two equations from the previous step, we have
✔ m/s) t
t²
5 m/
m/s) t
t + 0.
m) + (E
5
When we simplify into the quadratic form at2 + bt + c = 0 where a = 1, we have the following quadratic equation in the variable t. Remember to pay attention to the signs of the coefficient
and constant when entering the answers.
t² +
X
The response you submitted has the wrong sign. s) t+
s) t
X
The response you submitted has the wrong sign. s²)
= 0
Transcribed Image Text:and = 0 + 0 + 1/2/( 2 0.13 Xopponent (xo)opponent + (vo)opponent t + 0.13 0.13 m/s²t² 9.5✔ 9.5 m) + (5 ✔ m/s²) t² = ( 5✔ 9.5 opponent Step 2 When the players are side by side, Xplayer = Xopponent. Equating the right-hand sides of the two equations from the previous step, we have ✔ m/s) t t² 5 m/ m/s) t t + 0. m) + (E 5 When we simplify into the quadratic form at2 + bt + c = 0 where a = 1, we have the following quadratic equation in the variable t. Remember to pay attention to the signs of the coefficient and constant when entering the answers. t² + X The response you submitted has the wrong sign. s) t+ s) t X The response you submitted has the wrong sign. s²) = 0
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