Steady and Transient state of heat transfer by the help of an example.
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Steady and Transient state of heat transfer by the help of an example.
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- hello my question is about thermodynamics. and i am having troubles with writing energy balances . more specifically energy balance on closed , open , steady state and for throttling deviceAn open system is often referred to as control volume, which is a properly selected region in space in which mass and energy can flow across the boundaries as figure 1.2. The boundary of a open thermodynamic system is called the control surface Across the Boundaries E = Yes F 0 = Yes w =Yes Control surface ass YES W CONTROL VOLUME energy YES Figure 1.2. A cooling/heating radiator is an example of such a system – give two more examples of such a system.A certain ideal gas (unknown) inside a close piston-cylinder assembly undergoes a set of processes that composed of Isothermal expansion from State point 1 to state point 2, Isometric heat rejection from state point 2 to state point 3, and Isentropic compression from state point 3 back to the initial condition. If the maximum pressure is 3000kPa and maximum and minimum volume is 200cm³ and 50cm?, analyze the problem and perform the following: a. Draw and label the graph of this set of processes in the P-V and T-S diagram showing the state point numbers and energy directions. b. From the known ideal gases as shown in Table 1.0, select the best suited ideal gas to attain the processes stated if the lowest pressure is limited to 629.8kPa. Assume a constant specific heat. c. For the selected ideal gas from b, compute the work of compression (kJ/kg), work of expansion (kJ/kg), and heat rejected (kJ/kg) Table 1.0: Ideal gas specific heats of various common gases Gas constant, R kJ/kg-K Kikg.…
- A certain ideal gas (unknown) inside a close piston-cylinder assembly undergoes a set of processes that composed of Isothermal expansion from State point 1 to state point 2, Isometric heat rejection from state point 2 to state point 3, and Isentropic compression from state point 3 back to the initial condition. If the maximum pressure is 3000kPa and maximum and minimum volume is 200cm³ and 50cm', analyze the problem and perform the following: a. Draw and label the graph of this set of processes in the P-V and T-S diagram showing the state point numbers and energy directions. b. From the known ideal gases as shown in Table 1.0, select the best suited ideal gas to attain the processes stated if the lowest pressure is limited to 629.8kPa. Assume a constant specific heat. c. For the selected ideal gas from b, compute the work of compression (kJ/kg), work of expansion (kJ/kg), and heat rejected (kJ/kg) Table 1.0: Ideal gas specific heats of various common gases Gas constant, R Gas Formula…A certain ideal gas (unknown) inside a close piston-cylinder assembly undergoes a set of processes that composed of Isothermal expansion from State point 1 to state point 2, Isometric heat rejection from state point 2 to state point 3, and Isentropic compression from state point 3 back to the initial condition. If the maximum pressure is 3000kPa and maximum and minimum volume is 200cm and 50cm', analyze the problem and perform the following: a. Draw and label the graph of this set of processes in the P-V and T-S diagram showing the state point numbers and energy directions. b. From the known ideal gases as shown in Table 1.0, select the best suited ideal gas to attain the processes stated if the lowest pressure is limited to 629.8kPa. Assume a constant specific heat. c. For the selected ideal gas from b, compute the work of compression (kJ/kg), work of expansion (kJ/kg), and heat rejected (kJ/kg) Table 1.0: Ideal gas specific heats of various common gases Gas constant, R kJ/kg-K kikg K…Show detailed step by step solution. Topic: Thermodynamics
- number 1 A food product containing 82% moisture content is being frozen. Estimate the specific heat of the product at -8 ° C when 82% of the water is frozen. The specific heat of the dry product is 2.5 kJ / (kg ° C). It is assumed that the specific heat of water at -10 ° C is the same as the specific heat of water at 0 ° C, and that the specific heat of ice follows the function Cp es = 0.0062 T Frozen + 2.0649. Cp of frozen product = kJ / kg ° C.J. P. Holman, Heat transfer please can you solve it with keyboard, take your timeDerive a control volume form of the second law of thermodynamics.Suggest some practical uses for your relation inanalyzing real fl uid fl ows.
- How much ice (by mass) at a temperature of -19.9 degrees Celsius must be added to 325g of liquid water at a temperature of 60.1 degrees Celsius in order for the final temperature of both to reach 21 degrees Celsius. c of ice=2100 J/kg/C c of water=4190 J/kg/C Latent heat of fusion of water=3.34E5 J/kg/C a. .115kg b. 12kg c. 5 lbs d. .191kgCreate two problem solving about steady-state heat flow (Heat convection in fluids) and show your solutions. Thank you!Drag and Drop the correct answers in the blanks. A mass mis hanging from the end of a vertical spring that has a spring constant k. The equilibrium position of the mass, yo, is The total potential energy of the mass when it is displaced by s from the equilibrium position is given by Y. is zero + U(s) = ks + positive * negative 1 1 ks+ 21 + U(s) ks² + mgyo %3D U(s) mgyo