Complete Question 1,2,3 1. Look back at the 5 rows of corn you counted for the dihybrid cross.2. State the null hypothesis:3. Create a table below and conduct a Chi squared test on the data you collected.4. Calculate the degrees of freedom.Table 5-2Critical Values of the X2 Distributiondf0.9950.9750.90.50.10.050.0250.010.005 df.000.0000.4551.38610.0162.7063.8415.0246.6357.879 120.0100.0510.2114.6055.9917.3789.210 10.597 230.0720.2160.5842.3666.2517.8159.34811.345 12.838 30.2070.4841.0643.3577.7799.488 11.14313.27714.860 450.412 0.8311.6104.3519.236 11.07012.832 15.086 16.750 50.6760.9891.3441.2371.69062.2045.348 10.645 12.592 14.449 16.812 18.548 672.8336.346 12.017 14.067 16.013 18.475 20.278 782.1803.4907.344 13.362 15.507 17.535 20.090 21.955 81.7352.7004.1688.343 14.68416.919 19.023 21.666 23.589 9102.1563.2474.8659.342 15.987 18.307 20.483 23.209 25.188 10112.6033.8165.578 10.341 17.27519.675 21.920 24.725 26.757 11123.0744.4046.30411.340 18.549 21.026 23.337 26.217 28.300 125.0094.075 5.6296.262133.5657.042 12.340 19.812 22.362 24.73627.688 29.819 13147.790 13.339 21.064 23.685 26.119 29.141 31.319 14154.6018.54714.339 22.307 24.996 27.488 30.578 32.801 155.6. What are your conclusions from the Chi squared test?

Hypothesis is a general statement about the parameter of population like mean, standard deviation…

Answered: State the null hypothesis:

Science

Biology

State the null hypothesis:

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter3: Transmission Of Genes From Generation To Generation

Section3.7: Mendelian Inheritance In Humans

Problem 2EG: For most cases, a p value of 0.05 is used to determine whether results fit expected values. Is this...

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Question

Complete Question 1,2,3

1. Look back at the 5 rows of corn you counted for the dihybrid cross.
2. State the null hypothesis:
3. Create a table below and conduct a Chi squared test on the data you collected.
4. Calculate the degrees of freedom.
Table 5-2
Critical Values of the X2 Distribution
df
0.995
0.975
0.9
0.5
0.1
0.05
0.025
0.01
0.005 df
.000
.000
0.455
1.386
1
0.016
2.706
3.841
5.024
6.635
7.879 1
2
0.010
0.051
0.211
4.605
5.991
7.378
9.210 10.597 2
3
0.072
0.216
0.584
2.366
6.251
7.815
9.348
11.345 12.838 3
0.207
0.484
1.064
3.357
7.779
9.488 11.143
13.277
14.860 4
5
0.412 0.831
1.610
4.351
9.236 11.070
12.832 15.086 16.750 5
0.676
0.989
1.344
1.237
1.690
6
2.204
5.348 10.645 12.592 14.449 16.812 18.548 6
7
2.833
6.346 12.017 14.067 16.013 18.475 20.278 7
8
2.180
3.490
7.344 13.362 15.507 17.535 20.090 21.955 8
1.735
2.700
4.168
8.343 14.684
16.919 19.023 21.666 23.589 9
10
2.156
3.247
4.865
9.342 15.987 18.307 20.483 23.209 25.188 10
11
2.603
3.816
5.578 10.341 17.275
19.675 21.920 24.725 26.757 11
12
3.074
4.404
6.304
11.340 18.549 21.026 23.337 26.217 28.300 12
5.009
4.075 5.629
6.262
13
3.565
7.042 12.340 19.812 22.362 24.736
27.688 29.819 13
14
7.790 13.339 21.064 23.685 26.119 29.141 31.319 14
15
4.601
8.547
14.339 22.307 24.996 27.488 30.578 32.801 15
5.
6. What are your conclusions from the Chi squared test?

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