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Start with a 500 ml solution of 1.0 M Benzoic Acid with a pKa of 4.2. Now you add in enough grams of conjugate base (NaC6H5CO₂) to make the pH 4.3. Could you determine without a calculator: a. b. C. You have a higher molarity of acid than conjugate base You have a higher molarity of conjugate base than acid Not enough information

Start with a 500 ml solution of 1.0 M Benzoic Acid with a pKa of 4.2. Now you add in enough grams of conjugate base (NaC6H5CO₂) to make the pH 4.3. Could you determine without a calculator: a. b. C. You have a higher molarity of acid than conjugate base You have a higher molarity of conjugate base than acid Not enough information

Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter13: Acids And Bases
Section: Chapter Questions
Problem 149AE
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Start with a 500 ml solution of 1.0 M Benzoic Acid with a pKa of 4.2.  Now you add in enough grams of conjugate base (NaC6H5CO2) to make the pH 4.3. Could you determine without a calculator:

a. You have a higher molarity of acid than conjugate base

b. You have a higher molarity of conjugate base than acid

c. Not enough information

 

Start with a 500 ml solution of 1.0 M Benzoic Acid with a pKa of 4.2. Now you add in enough grams of conjugate base (NaC6H5CO2) to make the pH 4.3. Could you determine without a calculator: a. You have a higher molarity of acid than conjugate base b. You have a higher molarity of conjugate base than acid C. Not enough information
Transcribed Image Text:Start with a 500 ml solution of 1.0 M Benzoic Acid with a pKa of 4.2. Now you add in enough grams of conjugate base (NaC6H5CO2) to make the pH 4.3. Could you determine without a calculator: a. You have a higher molarity of acid than conjugate base b. You have a higher molarity of conjugate base than acid C. Not enough information
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