Solve using Bernoulli's Equation. y(6y^2 - x - 1) dx +2x dy = 0

Q: «) sin3x sinlx dY

A: See the details solution in below

Q: dx sin*x

A: We have to integrate.

Q: solve dy/dx

A: Given: y=log57x3x+2ln(5)To find : dydx=?Formula: (logax)'=1x ln a

Q: 7xyºdy - (2y² - x²)dx = 0

A:

Q: cosh / 2x 18) dx Vx² sinh³ /2x

A: The given integral: This can be rewritten as, To evaluate the integral: Apply linearity the above…

Q: y=Arccos (x²)

A:

Q: ( sinh3x cosh³x dx

A: Consider the integration as I=∫sinh3xcosh3xdx

Q: (x-7) dx 19. SJ5-4x-x2

A: Answer is following.

Q: arccos 2x dx 3.

A: We will use integration by parts. The solution is given below.

Q: 14. √ √2-√x dx

A:

Q: ial equation (x2 + 2xy)dy = (2xy + 3y²)dx

A:

Q: 2 Solve equation (D² +1)y-secx tan x using method of variation of parameters. %3D

A:

Q: Solve differential equetion. = 8X+_5X dx 4-202

A:

Q: 3. dx (sinh(2xV1+x du

A:

Q: dy -y3tanx dx Solve sin2x

A: The given differential equation is: sin(2x) dydx-y=tan(x)

Q: y' = (x+y– 2)² (х-у)?

A:

Q: sech²x -dx tanh(x)v1-tanh²x ix.

A: Solution is given below:

Q: sech - x dx , 0 < x < 1

A:

Q: solve parameter method J-yこ cosh x y"-

A:

Q: Solve the differential equation using variation of parameters

A:

Q: ① Solveing dy - - x dx = 。 ㅎ

A:

Q: Solve by Integrating Factor: y' = 1+3y cotx

A: The solution is given as

Q: dx 20.5 x√4x²-49

A:

Q: sech x dx , 0 < x < 1

A:

Q: 2. x³ydx+(3x² - y³ )]dy=0

A:

Q: Solve (cosx)dy = (sinx)dx

A: The objective is to solve the expression cosxdy=sinxdx

Q: Solve the differential equation = by the method of separating the variables. %3D

A: Given : dydx = 13y2

Q: 5. x?e-3x dx

A: ∫x2e-3xdx

Q: how to solve this equation using variation of parameters.    y'' + y = tanx

A:

Q: solve sin2x dy -y=tanx dx

A:

Q: .2 x² arctan(3x) dx %3D

A:

Q: 2e3* sin 2x dx

A:

Q: 4x² sinh (x³) tanh (x³) dx

A:

Q: cos(2x) dx sinx+cosx dx Vex

A: Find your answer below

Q: sec“ x (Vtan3 x +1) dx (Vtan3, Px+1) 4

A:

Q: Solve to find general solution: dy = Exe xez -1 1-x²y dx

A:

Q: 2. Solve the DE: -+secx(y-2sec³x+2 sec² x tan x) + y cotx=0 dx

A:

Q: (2x-3y)dx+(2y-3x)dy3D0

A:

Q: Jam sin(10x) dx

A:

Q: Se-Ax .sinh(2x) dx

A: We know, sinh(x)=ex-e-x2

Q: y = tan e³x + etan3x

A: (tan x)' = sec2(x) (eax)' = a eax.

Q: (0.2t25x+3x²) dx

A: We have to find the value of ∫050.2+25x+3x2dx using the Trapezoidal rule We take that the number of…

Q: 1- S 9-4x2 dx 2 - x tan- x dx

A: 1.Given integral,               ∫9-x2xdx

Q: Exact Equation 1. (6х + у?)dx + y(2х — Зу) %3 0

A:

Q: Solve DE using Bernoullis Equation

A: NOTE: Refresh your page if you can't see any equations. . take reciprocal on both sides…

Q: [ sec" x (Vtan' x+ 1) +1) dx 2. 4 sec'x 3

A:

Q: (ii) sec2 (x) dx

A:

Q: solve using Firs Order Linear Differential Equation

A: Topic:- differential equations

Q: SVx² + 10x + 25 dx. (cos4*x – sin4*x)dx dx

A: