Solve the differential equation by variation of parameters. y" + 3y + 2y = 2 + ex Step 1 We are given a nonhomogeneous second-order differential equation. Similar to the method of solving by undetermined coefficients, we first find the complementary function y for the associated homogeneous equation. This time, the particular solution y is based on Wronskian determinants and the general solution is y = Yc+Yp' First, we must find the roots of the auxiliary equation for y" + 3y' + 2y = 0. m² +3m + 2 = 0 Solving for m, the roots of the auxiliary equation are as follows. smaller value larger value m₁ = m₂ =

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.1: Solutions Of Elementary And Separable Differential Equations
Problem 15E: Find the general solution for each differential equation. Verify that each solution satisfies the...
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Solve the differential equation by variation of parameters.
y" + 3y' + 2y =
1
2 + ex
Step 1
We are given a nonhomogeneous second-order differential equation. Similar to the method of solving by undetermined coefficients, we first find the complementary function Yc for the
associated homogeneous equation. This time, the particular solution y, is based on Wronskian determinants and the general solution is y = y + Yp
P
First, we must find the roots of the auxiliary equation for y" + 3y' + 2y = 0.
m² +3m + 2 = 0
Solving for m, the roots of the auxiliary equation are as follows.
smaller value
larger value
m₁ =
m₂ =
Transcribed Image Text:Solve the differential equation by variation of parameters. y" + 3y' + 2y = 1 2 + ex Step 1 We are given a nonhomogeneous second-order differential equation. Similar to the method of solving by undetermined coefficients, we first find the complementary function Yc for the associated homogeneous equation. This time, the particular solution y, is based on Wronskian determinants and the general solution is y = y + Yp P First, we must find the roots of the auxiliary equation for y" + 3y' + 2y = 0. m² +3m + 2 = 0 Solving for m, the roots of the auxiliary equation are as follows. smaller value larger value m₁ = m₂ =
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