Solution: -T/20 u=t F(w) = = 10 Integrating by parts with; du = dt and 2 20 T CT/2 -icot F(0) = f(t) e ¹³ dt = [7727²7 ² -te -T/2 e f(t) 23/10/20 -iwT/2 2. T :{- T-iw -1 T/2 le-toot -iw COS -iw +eT/2 77/2 @T 2 J-T/2 + 2i @² + - t -2i e -iw.iw -2i e -icot sin- dv = e -toT/2 ωT f(t)= 77/2 -ioot dt 2i @ f(t)= = -iot dt -T/2 } +elT/2 1-(-1) T 1---²-2 COS @T 2 4i 2 Tw² = -iot -io @T 2 sin-

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter9: Multivariable Calculus
Section9.3: Maxima And Minima
Problem 20E
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Solution:
F(w) =
u=t
-T/2 O
=
10
2
F(w)= {]
T
27/₁1/²0
Integrating by parts with;
du = dt
and
2
- ²/1
=
f(t)
f(t)
= [ f(t)e-¹³ dt = |
е
T
T-iw
-1
T/2
-iot
te
- iw
-iw
77/2
J-T/2
-iwT/2
+eT/2
e
+
+
t
-2i
@T 2i
COS @²
2
T/2 2
e-icot
-iw.iw
-2i e
sin-
-T/2T
dv = e
-i@T/2
oᎢ .
2
f(t)=
-te
-}=
7/2
-iot
-T/2
+e"
@²
2i
-iont dt
f(t)=
=
dt
}
iwT/2
1-(-1)
T
T
1-(-5)
2
2
COS
@T
2
2/₁
-iwt
-io
4i ωT
sin-
Tw²
2
Transcribed Image Text:Solution: F(w) = u=t -T/2 O = 10 2 F(w)= {] T 27/₁1/²0 Integrating by parts with; du = dt and 2 - ²/1 = f(t) f(t) = [ f(t)e-¹³ dt = | е T T-iw -1 T/2 -iot te - iw -iw 77/2 J-T/2 -iwT/2 +eT/2 e + + t -2i @T 2i COS @² 2 T/2 2 e-icot -iw.iw -2i e sin- -T/2T dv = e -i@T/2 oᎢ . 2 f(t)= -te -}= 7/2 -iot -T/2 +e" @² 2i -iont dt f(t)= = dt } iwT/2 1-(-1) T T 1-(-5) 2 2 COS @T 2 2/₁ -iwt -io 4i ωT sin- Tw² 2
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