Sodium hydroxide reacts with carbon dioxide as follows: 2NaOH(s)+CO2(g)→Na2CO3(s)+H2O(l)   How many moles of Na2CO3 can be produced?

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter3: Chemical Reactions
Section: Chapter Questions
Problem 121QRT: Ammonia can be formed by a direct reaction of nitrogen and hydrogen. N2(g) + 3 H2(g) 2 NH3(g) A...
icon
Related questions
Question
100%

Sodium hydroxide reacts with carbon dioxide as follows:

2NaOH(s)+CO2(g)→Na2CO3(s)+H2O(l)

 

How many moles of Na2CO3 can be produced?

I Review I Constants I Periodic Table
Sodium hydroxide reacts with carbon dioxide as follows:
Submit
Previous Answers
2NaOH(s) + CO2(g) → Na2 CO3 (s) + H20(1)
Correct
The limiting reactant is the one that is completely consumed during the reaction. According to the reaction stoichiometry, two
moles of NaOH are consumed per one mole of CO2 in a complete reaction. The amount of NaOH needed for a complete
consumption of 1.20 mol CO2 is
2 mol NaOH
mol NaOH needed to react
1.20 mol CO, x
1 mol CO,
2.40 mol NaOH
Since only 2.30 mol NaOH are available, NaOH will run out before all CO2 reacts. Therefore, NaOH is the limiting reactant.
Part B
How many moles of Na2 CO3 can be produced?
Express your answer in moles to two decimal places.
Α φ.
?
n = |1.31
mol
Submit
Previous Answers Request Answer
X Incorrect; Try Again; 3 attempts remaining
Transcribed Image Text:I Review I Constants I Periodic Table Sodium hydroxide reacts with carbon dioxide as follows: Submit Previous Answers 2NaOH(s) + CO2(g) → Na2 CO3 (s) + H20(1) Correct The limiting reactant is the one that is completely consumed during the reaction. According to the reaction stoichiometry, two moles of NaOH are consumed per one mole of CO2 in a complete reaction. The amount of NaOH needed for a complete consumption of 1.20 mol CO2 is 2 mol NaOH mol NaOH needed to react 1.20 mol CO, x 1 mol CO, 2.40 mol NaOH Since only 2.30 mol NaOH are available, NaOH will run out before all CO2 reacts. Therefore, NaOH is the limiting reactant. Part B How many moles of Na2 CO3 can be produced? Express your answer in moles to two decimal places. Α φ. ? n = |1.31 mol Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 1 images

Blurred answer
Knowledge Booster
Stoichiometry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry: The Molecular Science
Chemistry: The Molecular Science
Chemistry
ISBN:
9781285199047
Author:
John W. Moore, Conrad L. Stanitski
Publisher:
Cengage Learning
Chemistry for Engineering Students
Chemistry for Engineering Students
Chemistry
ISBN:
9781285199023
Author:
Lawrence S. Brown, Tom Holme
Publisher:
Cengage Learning
Chemistry for Engineering Students
Chemistry for Engineering Students
Chemistry
ISBN:
9781337398909
Author:
Lawrence S. Brown, Tom Holme
Publisher:
Cengage Learning
Introduction to General, Organic and Biochemistry
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:
9781285869759
Author:
Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:
Cengage Learning
Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
Chemistry
ISBN:
9781337399425
Author:
Steven S. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
Chemistry
ISBN:
9781285199030
Author:
Steven S. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning