Given the content of memory and the registers below.i. ii. iii.Indicate the type of addressing mode of each line of instruction belowDeduce the target addressDeduce the Value loaded into accumulator register (A) Data at locationMemory Address036003030103000360000C3036390003030C303Memory contentBase Register (B)00600Program Counter (Pc)003000Index Register (X)000090Register ContentInstructionsOpcodes - LDA = 00SNopcoden i x b p eDisplacementTarget Address (TA)10000001 1 0 0 1 00110 0000 000020000001 1 1 1 0 00011 0000 000030000001 0 0 0 1 00000 0011 000040000000 1 0 0 0 00000 0011 000050000001 1 0 0 0 10000 1100 0011 0000 0011

SN opcode n i x b p e Displacement Target Address (TA) 1 000000 1 1 0 0 1 0 0110 0000 0000 2 000000 1 1 1 1 0 0 0011 0000 0000 3 000000 1 0 0 0 1 0 0000 0011 0000 4 000000 0 1 0 0 0 0 0000 0011 0000 5 000000 1 1 0 0 0 1 0000 1100 0011 0000 0011

SN opcode n i x b p e Displacement Target Address (TA) 1 000000 1 1 0 0 1 0 0110 0000 0000 2 000000 1 1 1 1 0 0 0011 0000 0000 3 000000 1 0 0 0 1 0 0000 0011 0000 4 000000 0 1 0 0 0 0 0000 0011 0000 5 000000 1 1 0 0 0 1 0000 1100 0011 0000 0011

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter4: Processor Technology And Architecture

Section: Chapter Questions

Problem 15VE: A(n) ________________ instruction always alters the instruction execution sequence. A(n)...

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Concept explainers

Fundamentals of Input and Output Performance

The I/O subsystem is a component of computer system design that uses buses to assist communication between the Central Processing Unit, Computer Memory/Storage, and Input and Output Devices (that is known as peripheral devices). The I/O subsystem includes disc controllers, tape drives, discs, system buses, and other devices. The I/O database application reads and writes drives using the operating system windows I/O.

Question

Given the content of memory and the registers below.

i. ii. iii.	Indicate the type of addressing mode of each line of instruction below
Deduce the target address Deduce the Value loaded into accumulator register (A)

Data at location	Memory Address
03600	3030
103000	3600
00C303	6390
003030	C303

Memory content

Base Register (B)	00600
Program Counter (Pc)	003000
Index Register (X)	000090

SN	opcode	n i x b p e	Displacement	Target Address (TA)
1	000000	1 1 0 0 1 0	0110 0000 0000
2	000000	1 1 1 1 0 0	0011 0000 0000
3	000000	1 0 0 0 1 0	0000 0011 0000
4	000000	0 1 0 0 0 0	0000 0011 0000
5	000000	1 1 0 0 0 1	0000 1100 0011 0000 0011

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