Situation 2: The butt connection shows 8- 22 mm diameter A325 bolts spaced as shown. The diameter of the hole is 3 mm larger than the bolts. The thickness of the middle plate is 16 mm while the other plates are 12 mm. Use Si = 40 mm, S2 = 80 mm, Sa = 50 mm and S4 = 100 mm. S, S2 S, Allowable stresses are as follows: Steel yield strength, Fy = 248 MPa Steel ultimate strength, Fu = 400 MPa Bolt shear stress, Ex = 120 MPa Bearing Stress on projected area, ER = 600 MPa Tensile stress on gross area = 148 MPa Tensile stress on net area = 200 MPa Shear stress on plates = 120 MPa Determine the value of T based on bolt shear. a. 364.93 kN с. 378.88 kN b. 844.80 kN d. 352.00 kN 7. Find the value of T based on bearing of plates. 6.

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter1: Tension, Compression, And Shear
Section: Chapter Questions
Problem 1.8.10P: A steel punch consists of two shafts: upper shaft and lower shaft. Assume that the upper shaft has a...
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S2 - 9 and 10
Situation 2:
The butt connection shows 8 – 22 mm diameter
A325 bolts spaced as shown. The diameter of the
hole is 3 mm larger than the bolts. The thickness of
the middle plate is 16 mm while the other plates
are 12 mm. Use Si = 40 mm, S2 = 80 mm, S3 = 50
mm and S4 = 100 mm.
S,
S2
S,
Allowable stresses are as follows:
Steel yield strength, Fy = 248 MPa
Steel ultimate strength, Fu = 400 MPa
Bolt shear stress, Ex = 120 MPa
Bearing Stress on projected area, ER = 600 MPa
Tensile stress on gross area = 148 MPa
Tensile stress on net area = 200 MPa
Shear stress on plates = 120 MPa
6.
Determine the value of T based on bolt shear.
a.
364.93 kN
с.
378.88 kN
b.
844.80 kN
d.
352.00 kN
Find the value of I based on bearing of plates.
7.
а.
364.93 kN
с.
378.88 kN
b.
844.80 KN
d.
352.00 kN
8.
Compute the value of T based on tension on the gross area.
а.
364.93 kN
c.
378.88 kN
b.
844.80 kN
d.
352.00 kN
9.
Solve the value of T based on tension on the net area.
а.
364.93 kN
с.
378.88 kN
b.
844.80 kN
d.
352.00 kN
Transcribed Image Text:Situation 2: The butt connection shows 8 – 22 mm diameter A325 bolts spaced as shown. The diameter of the hole is 3 mm larger than the bolts. The thickness of the middle plate is 16 mm while the other plates are 12 mm. Use Si = 40 mm, S2 = 80 mm, S3 = 50 mm and S4 = 100 mm. S, S2 S, Allowable stresses are as follows: Steel yield strength, Fy = 248 MPa Steel ultimate strength, Fu = 400 MPa Bolt shear stress, Ex = 120 MPa Bearing Stress on projected area, ER = 600 MPa Tensile stress on gross area = 148 MPa Tensile stress on net area = 200 MPa Shear stress on plates = 120 MPa 6. Determine the value of T based on bolt shear. a. 364.93 kN с. 378.88 kN b. 844.80 kN d. 352.00 kN Find the value of I based on bearing of plates. 7. а. 364.93 kN с. 378.88 kN b. 844.80 KN d. 352.00 kN 8. Compute the value of T based on tension on the gross area. а. 364.93 kN c. 378.88 kN b. 844.80 kN d. 352.00 kN 9. Solve the value of T based on tension on the net area. а. 364.93 kN с. 378.88 kN b. 844.80 kN d. 352.00 kN
STEEL DESIGN
10.
Calculate the value of T based on block shear.
a.
608 kN
с.
496 KN
b.
480 kN
d.
421 kN
Transcribed Image Text:STEEL DESIGN 10. Calculate the value of T based on block shear. a. 608 kN с. 496 KN b. 480 kN d. 421 kN
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