Show that the total force on a rectangular dam due to the water behind it increases with the square of the water depth. In particular, show that this force is given by F= pgh, where p is the density of water, h is its depth at the dam, and L is the length of the dam. You may assume the face of the dam is vertical. (Hint: Calculate the average pressure exerted and multiply this by the area in contact with the water. (See the figure below.) Submit a file with a maximum size of 1 MB.) F=PA P-hpg

Principles of Physics: A Calculus-Based Text
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Author:Raymond A. Serway, John W. Jewett
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Chapter15: Fluid Mechanics
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Problem 14P: Review. The tank in Figure P15.13 is filled with water of depth d. At the bottom of one sidewall is...
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Show that the total force on a rectangular dam due to the water behind it increases with the square of the water depth. In particular, show that this force is given by F = pgh²L, where p is the density of water, h is its depth at the dam, and
2
L is the length of the dam. You may assume the face of the dam is vertical. (Hint: Calculate the average pressure exerted and multiply this by the area in contact with the water. (See the figure below.) Submit a file with a maximum size of
1 MB.)
F
F = PA
P=hpg
Transcribed Image Text:Show that the total force on a rectangular dam due to the water behind it increases with the square of the water depth. In particular, show that this force is given by F = pgh²L, where p is the density of water, h is its depth at the dam, and 2 L is the length of the dam. You may assume the face of the dam is vertical. (Hint: Calculate the average pressure exerted and multiply this by the area in contact with the water. (See the figure below.) Submit a file with a maximum size of 1 MB.) F F = PA P=hpg
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