Sheet 1.3m A. 300mm Е - зообра Ps L 2.5m Aluminumn L = 4m A = 500mm E = 706PS ^ Pa =
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- 80k N 7 p+ رس: 200k 600 Ax GOC MPL 30+ विरत y Q Fin Force for all member?Please provide the complete solution for the Pm. Thank you! QA = 346.320 BTU QR = -208.981 BTU V4 = 31.818 ft^3 V2 = 18 ft^3cylindrical pressure vessel has inside diameter d_{o} = 500 mm and inside diameter di=490 mm.if it i made of carbon steel SAE 1040 OQT1300, find the maximum allowable internal pressure if the safety factor against yielding is not to be less than 4. Neglect the external pressure and assume that the longitudinal stresses are taken by the vessel itself. a) Solve using the MSST. b) Solve using the DET. See Appendix 3 for material properties.
- b) Determine the maximum gas pressure and the dimensions of cross -section of the connecting rod for a diesel engine with the following data: (i) Cylinder bore 120 mm and the Length of connecting rod = 360mm (ii) The critical buckling load = 407.1504 KN; (iii) The compressive yield stress =330 N/mm? ; Factor of safety = 6 %3D %3DQuesron L UESTION from beading Support Diperenticte nomal caial looding your answer with neat explanatory sketches that show the possible tyes f type of loading de formation resulting from eachFigure 1 shows a composite shaft ABCD acted upon horizontal forces. The moduli of elasticity and the cross-section areas of the segments of the shaft are also provided. Eal = 70 GPa AAB = 58 mm2 Ecu = 126 GPa Est AcD = 39 mm2 = 200 GPa ABC = 77 mm2 %3D %3D Copper 20kN 8 kN Aluminum Steel 7 kN A B 20kN D 8 kN 450 mm 300 mm - 400 mm Figure 1: Axially loaded composite shaft 2.1. Construct the diagram of internal normal forces for each cross-section of the shaft (6) 2.2. Calculate the displacement of the point C with respect to the fixed-point A. (3) 2.3. If the shaft must have one uniform diameter, determine the required minimum diameter of the shaft if the normal yield stress in the composite shaft must not exceed 450 MPa with a factor of safety equal to 1.8. (11)
- a=3 CVE 349 HOMEWORK 1 b=2.5 Q.1. d=3 P=12 27 9. a *Analyze the structure under given loading. *Design members 14,12,42,45,43,23,53 *Design joints 1,2,3,4 and 5. * Use parameters that are assigned to you. Those who use different parameters will be penalized and get 0. Units of a,b and c are meters and P is kN.A Brass C AL 0,6m B A = 1130 mm² T₁ = 10°C no load Calc stress at T= 50°C What is the displacemed of Cat T=SooC9:0. محو التحدید blä 10 FIND STRESS IN Aluminum. IF E st= .200000 MPa, Ealu.=7000O MPa 100 kN RALU.=30 MM Aluminum Steel no one 69 MPa 31 MPa 19 MPa 55 MPa bläi 10 find the shear stress in bolt in pin A 60 kN 1m RST = 20 MM
- I fc = 6000 psi WLL 3600 lb/ft WD=384 lb/ft Properties: As = 369 in² Ig = 50979 in* ct = 15.83 in cb = 20.17 in st=3527 in³ Sb = 3220 in ³ e = 13.12 in Aps = 1.53 in² ft = 930 psi fpi= 1189000 psi Given the applied load and properties of a simply supported I-beam, determine the initial prestressing condition at the bottom of the beam by using basic concept method. Span = 34 ftband Pass FI.. 目Readi This course EHide block An aluminum pipe is filled in concrete is subjected to a pure compressive force as shown in the figure below. Determine the factor of safety against compressive stress acting on the column. The pipe has an outer diameter of 60 mm and inner diameter of 50 mm. The aluminum and the polymer concrete have the following material properties: Young's modulus: Eal = 70 GPa (aluminum), Ecr = 30 GPa (concrete). Yield compressive strength: Sy-al = 180 MPa (aluminum), Sy-cr = 60 MPa (concrete). 100 kN 500 mm Select one: O FS = 1.7A piston rod, made of AISI 3140 steel, OQT 1000 F (Fig. AF 2), is subjected to a repeated, reversed load. The rod is for a 25-in. air compressor, where the maximum pressure is 125 psig. Compute the diameter of the rod using a design factor based on (a) ultimate strength, (b) yield strength. Use Su = 152.5 ksi and Sy = 132.5 ksi.