Score on last try: 0.33 of 1 pts. See Details for more. Get a similar question You can retry this question below Let T:R³ -> R³ be multiplication by -11 -1 2 95 10 -17 6 1 -1 1. The kernel of T is a line through the origin. Find a vector equation for it. 8 У = t 1 -5 12 2. The range of T is a plane through the origin. Find an equation for it. 2 + ✓ 2 y + ✓ -3 E N = 0
Score on last try: 0.33 of 1 pts. See Details for more. Get a similar question You can retry this question below Let T:R³ -> R³ be multiplication by -11 -1 2 95 10 -17 6 1 -1 1. The kernel of T is a line through the origin. Find a vector equation for it. 8 У = t 1 -5 12 2. The range of T is a plane through the origin. Find an equation for it. 2 + ✓ 2 y + ✓ -3 E N = 0
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter8: Applications Of Trigonometry
Section8.3: Vectors
Problem 16E
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Help im not sure where I got it wrong
![Score on last try: 0.33 of 1 pts. See Details for more.
Get a similar question You can retry this question below
Let T:R³ -> R³ be multiplication by
-11
-1
2
95 10 -17
6 1
-1
1. The kernel of T is a line through the origin. Find a vector equation for it.
8
У
=
t
1
-5
12
2. The range of T is a plane through the origin. Find an equation for it.
2
+
✓
2
y +
✓
-3
E
N
= 0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F65ce4946-20f3-402b-8a73-35e62e74d93e%2F908220a5-bb07-445f-bbf4-8a9b69a9cdea%2F4cfggse_processed.png&w=3840&q=75)
Transcribed Image Text:Score on last try: 0.33 of 1 pts. See Details for more.
Get a similar question You can retry this question below
Let T:R³ -> R³ be multiplication by
-11
-1
2
95 10 -17
6 1
-1
1. The kernel of T is a line through the origin. Find a vector equation for it.
8
У
=
t
1
-5
12
2. The range of T is a plane through the origin. Find an equation for it.
2
+
✓
2
y +
✓
-3
E
N
= 0
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